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denis23 [38]
3 years ago
9

Each step in any energy conversion process will _____.

Physics
1 answer:
jeyben [28]3 years ago
6 0
The answer is : <span>lose energy </span>
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Convert 3.5 km/hr to m/s
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Answer:

0.972222........

Explanation:

1. Convert km/h to m/h by multiplying by 1000

2. Divide by 60 so that you have 58.3333... meters per minute

3. Divide by 60 again so now you have 0.972222... m/s

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Answer this question thanks
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Displacement: Consider a deer that runs from point A to point B. The distance the deer runs can be greater than the magnitude of
adoni [48]

Answer:

The given statement concerning distance and displacement is true.

Explanation:

If any point travels along any path between two points A and B the distance it travels is the length of the actual path it travels.

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Mathematically S=\int |ds|

Displacement by definition  is the shortest distance between the initial and final positions of the particle and is given by the straight line joining the two points.

Since a line is the shortest path that exists between 2 points thus it will be always smaller than any other path connecting the 2 points hence will be smaller than the distance.

While as if the object travels along a straight line without changing it's direction the distance in that case equals the displacement.

4 0
3 years ago
72) What is the freezing point (°C) of a solution prepared by dissolving 11.3 g of Ca(NO3)2 (formula weight = 164 g/mol) in 115
Rina8888 [55]

<u>Answer:</u> The freezing point of solution is -3.34°C

<u>Explanation:</u>

Vant hoff factor for ionic solute is the number of ions that are present in a solution. The equation for the ionization of calcium nitrate follows:

Ca(NO_3)_2(aq.)\rightarrow Ca^{2+}(aq.)+2NO_3^-(aq.)

The total number of ions present in the solution are 3.

  • To calculate the molality of solution, we use the equation:

Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

Where,

m_{solute} = Given mass of solute (Ca(NO_3)_2) = 11.3 g

M_{solute} = Molar mass of solute (Ca(NO_3)_2) = 164  g/mol

W_{solvent} = Mass of solvent (water) = 115 g

Putting values in above equation, we get:

\text{Molality of }Ca(NO_3)_2=\frac{11.3\times 1000}{164\times 115}\\\\\text{Molality of }Ca(NO_3)_2=0.599m

  • To calculate the depression in freezing point, we use the equation:

\Delta T=iK_fm

where,

i = Vant hoff factor = 3

K_f = molal freezing point depression constant = 1.86°C/m.g

m = molality of solution = 0.599 m

Putting values in above equation, we get:

\Delta T=3\times 1.86^oC/m.g\times 0.599m\\\\\Delta T=3.34^oC

Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.

\Delta T=\text{freezing point of water}-\text{freezing point of solution}

\Delta T = 3.34 °C

Freezing point of water = 0°C

Freezing point of solution = ?

Putting values in above equation, we get:

3.34^oC=0^oC-\text{Freezing point of solution}\\\\\text{Freezing point of solution}=-3.34^oC

Hence, the freezing point of solution is -3.34°C

4 0
3 years ago
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