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4 years ago

Each step in any energy conversion process will _____.

Physics

1 answer:

jeyben [28]4 years ago

6 0

The answer is : <span>lose energy </span>

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CAN I HAVE SOME HELP PLEASE

AURORKA [14]

Answer:

By teh way is isn't it question of law or science and the picture is of what electric light or not I have read it so I was asking isn't is question of science

5 0

3 years ago

ich of the following is not accurate when describing solids? A. The amount of pressure exerted by a solid is solely dependent on

Dafna11 [192]

The amount of solid does not affect how you are describing the solid so a is the answer

5 0

3 years ago

Suppose that she pushes on the sphere tangent to its surface with a steady force of F = 75 N and that the pressured water provid

PolarNik [594]

Answer:

The time taken to rotate the sphere one time is, t = 22 s

Explanation:

Given data,

The mass of the sphere, m = 8200 kg

The radius of the sphere, r = 90 cm

= .9 m

The force applied by the girl, F = 75 N

The moment of inertia of the sphere is,

I = 2/5 mr²

= (2/5) 8200 x (.9)²

= 2657 kg·m²

The torque,

τ = I α

75 x 0.9 = 2657 x α

α = 0.0254 rad/s²

The angular displacement,

θ = ½αt²

2π = ½ x 0.0254 rad/s² x t²

t = 22 s

Hence, the time taken to rotate the sphere one time is, t = 22 s

8 0

3 years ago

A mass of 3.6 kg oscillate on a horizontal spring with a spring constant of 160 N/m.

Darya [45]

Answer:

48.7 J

Explanation:

For a mass-spring system, there is a continuous conversion of energy between elastic potential energy and kinetic energy.

In particular:

- The elastic potential energy is maximum when the system is at its maximum displacement

- The kinetic energy is maximum when the system passes through the equilibrium position

Therefore, the maximum kinetic energy of the system is given by:

$KE=\frac{1}{2}mv^2$

where

m is the mass

v is the speed at equilibrium position

In this problem:

m = 3.6 kg

v = 5.2 m/s

Therefore, the maximum kinetic energy is:

$KE=\frac{1}{2}(3.6)(5.2)^2=48.7 J$

6 0

3 years ago

If I have an object that starts from rest and reaches a velocity of 25m/s over a distance of 11m what is the acceleration of the

Elodia [21]

Answer:

Here is something that may help you!!

Explanation:

I found it in a cite (not that I'm plagiarizing, or anything).

3 0

3 years ago