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Nana76 [90]
3 years ago
9

Ball 1 is thrown to the ground with an initial downward speed; ball 2 is dropped to the ground from rest.

Physics
1 answer:
MariettaO [177]3 years ago
8 0

Answer:

equal to the change in gravitational potential energy of ball 2.

Explanation:

Change in gravitational potential energy is equal to work done by gravitational force on the body .

work done = force x displacement

force = mg

displacement = height ( h )

change in gravitational energy = mgh

Since mass is same in both the cases , g is also the same in both the cases and h too is same in both the cases . change in gravitational energy will be same in both the cases. Initial velocity will have no affect on the result at all.

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3 years ago
7. How long does it take a ball rolling down a hill to change its speed from 3 m/sec to 34.5 m/sec
lys-0071 [83]

The time elapsed is 9 seconds

Explanation:

The motion of the ball is a uniformly accelerated motion (a motion with constant acceleration), so we can use the following suvat equation:

v=u+at

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u = 3 m/s is the initial velocity

v = 34.5 m/s is the final velocity

a=3.5m/s^2 is the acceleration

Solving for t, we find the time taken for this change in velocity:

t=\frac{v-u}{a}=\frac{34.5-3}{3.5}=9 s

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true

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