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Nana76 [90]
3 years ago
9

Ball 1 is thrown to the ground with an initial downward speed; ball 2 is dropped to the ground from rest.

Physics
1 answer:
MariettaO [177]3 years ago
8 0

Answer:

equal to the change in gravitational potential energy of ball 2.

Explanation:

Change in gravitational potential energy is equal to work done by gravitational force on the body .

work done = force x displacement

force = mg

displacement = height ( h )

change in gravitational energy = mgh

Since mass is same in both the cases , g is also the same in both the cases and h too is same in both the cases . change in gravitational energy will be same in both the cases. Initial velocity will have no affect on the result at all.

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A hop is a springing from one foot but landing on the other foot? Question 4 options: True False
Rama09 [41]

Answer:

i thinc it's False

Explanation:

sorry im 6

6 0
3 years ago
Read 2 more answers
What is the answer for this. please the correct answer only​
omeli [17]

Answer:

C. 900J (i tried my best)

Explanation:

the student's mass=60kg

gravitational field strength= 10N/kg:

1kg = 10N

60kg = 600N

(where 600N is the gravitational field strength of the student)

√1.5²+2² (pythagoras theorem)

=2.5m (the stairs' length)

work done= N x distance move in the direction of force (m)

=600N x 2.5m

=1500J @ Nm

1500J - 600N (gravitational field strength of the student)

=900J(??)

-correct me if i'm wrong i'm just a human :)

5 0
4 years ago
Explain Using the equation for translational kinetic energy, show why a car moving at 40 m/s has four times the translational ki
djverab [1.8K]

Answer:

Explanation:

Equation for translational kinetic energy = 1/2 m V² where m is mass and V is velocity .

In first case let mass of car be m

Translational kinetic energy = 1/2 m x 40² = 800 m .

In the second case ,

Translational kinetic energy = 1/2 m x 20² = 200 m

So , in former case kinetic energy of car is 4 times that of second case.

7 0
3 years ago
Since many wavelengths of light are measured in nanometers, it's useful to know that planck's constant (h) multiplied with the s
MrRa [10]

Answer:

E = h f      and since f = c / λ     we have E = h c / λ

Thus  λ = h c / E

Also, 1 ev = 1.6E-19 C

λ = 6.63E-34 * 3.0E8 / (1.6 * 1.6E-19)

λ = 6.63 * 3.0 / (1.6 * 1.6) * E-7

λ = 7.77E-7 = 777 nanometers

(B) is correct

4 0
2 years ago
A mass (m = 30 g) falls onto a spring (k = 7.3 N/m) from a height (h = 25 cm). The spring compresses an additional amount x befo
yulyashka [42]

Answer:

x₁ = 0.1878 m

Explanation:

For this exercise we will use conservation of energy

starting point. Highest point

         Em₀ = U = m g h

final point. Lowest point with fully compressed spring

         Em_f = K_e + U

         Em_f = ½ K x² + m g x

         

energy is conserved

         Em₀ = Em_f

        m g h = ½ K x² + m g x

       ½ K x² + mg (x- h) = 0

         

let's substitute

       ½ 7.3 x² + 0.030 9.8 (x- 0.25) = 0

        3.65 x² + 0.294 (x- 0.25) = 0

        x² + 0.080548 (x- 0.25) = 0

        x² - 0.020137 + 0.080548 x = 0

        x² + 0.080548 x - 0.020137 = 0

let's solve the quadratic equation

      x = [0.080548 ±√ (0.080548² + 4   0.020137)] / 2

      x = [0.080548 ± 0.29502] / 2

      x₁ = 0.1878 m

      x₂ = -0.1072 m

These are the compression and extension displacement of the spring

4 0
3 years ago
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