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Nana76 [90]
2 years ago
9

Ball 1 is thrown to the ground with an initial downward speed; ball 2 is dropped to the ground from rest.

Physics
1 answer:
MariettaO [177]2 years ago
8 0

Answer:

equal to the change in gravitational potential energy of ball 2.

Explanation:

Change in gravitational potential energy is equal to work done by gravitational force on the body .

work done = force x displacement

force = mg

displacement = height ( h )

change in gravitational energy = mgh

Since mass is same in both the cases , g is also the same in both the cases and h too is same in both the cases . change in gravitational energy will be same in both the cases. Initial velocity will have no affect on the result at all.

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2 years ago
A cannon is fired horizontally at 243 m/s off of a 62 meter tall, shear vertical cliff. How far in meters from the base of the c
Alekssandra [29.7K]

Answer:

865.08 m

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 243 m/s

Height (h) of the cliff = 62 m

Horizontal distance (s) =?

Next, we shall determine the time taken for the cannon to get to the ground. This can be obtained as follow:

Height (h) of the cliff = 62 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

62 = ½ × 9.8 × t²

62 = 4.9 × t²

Divide both side by 4.9

t² = 62/4.9

Take the square root of both side.

t = √(62/4.9)

t = 3.56 s

Finally, we shall determine the horizontal distance travelled by the cannon ball as shown below:

Initial velocity (u) = 243 m/s

Time (t) = 3.56 s

Horizontal distance (s) =?

s = ut

s = 243 × 3.56 s

s = 865.08 m

Thus, the cannon ball will impact the ground 865.08 m from the base of the cliff.

6 0
2 years ago
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