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Dahasolnce [82]
3 years ago
9

· A 0.100g sample of Mg when combined with O2 yields 0.166g of Mgo, a

Chemistry
1 answer:
ddd [48]3 years ago
6 0

Answer:

m_{MgO}=0.239gMgO

Explanation:

Hello,

In this case, the chemical reaction between magnesium and oxygen to yield magnesium oxide is:

2Mg+O_2\rightarrow 2MgO

In such a way, for 0.144 g of magnesium reacting with sufficient oxygen, the mass of magnesium oxide, whose molar mass is 40.3 g/mol (2:2 mole ratio) turns out:

m_{MgO}=0.144gMg*\frac{1molMg}{24.3gMg} *\frac{2molMgO}{2molMg}* \frac{40.3gMgO}{1molMgO} \\\\m_{MgO}=0.239gMgO

Best regards.

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6 0
3 years ago
g A laboratory analysis of an unknown compound found the following composition: C 75.68% ; H 8.80% ; O 15.52%. What is the empir
sammy [17]

Answer:

THE EMPIRICAL FORMULA FOR THE UNKNOWN COMPOUND IS C7H9O

Explanation:

The empirical formula for the unknown compound can be obtained by following the processes below:

1 . Write out the percentage composition of the individual elements in the compound

C = 75.68 %

H = 8.80 %

O = 15.52 %

2. Divide the percentage composition by the atomic masses of the elements

C = 75 .68 / 12 = 6.3066

H = 8.80 / 1 = 8.8000

O = 15.52 / 16 = 0.9700

3. Divide the individual results by the lowest values

C = 6.3066 / 0.9700 = 6.5016

H = 8.8000 / 0.9700 = 9.0722

O = 0.9700 / 0.9700 = 1

4. Round up the values to the whole number

C = 7

H = 9

O = 1

5 Write out the empirical formula for the compound

C7H90

In conclusion, the empirical formula for the unknown compound is therefore C7H9O

7 0
3 years ago
Attractive forces of liquids allow for _____.
kap26 [50]

Answer:

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Explanation:

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3 0
3 years ago
Read 2 more answers
Part A
PilotLPTM [1.2K]

Answer:

4200ml

Explanation:

Converting 3.1kg to g

3.1*1000= 3100g

Since density = mass/volume, then

volume = mass/ density

Therefore volume = 3100/0.74

= 4189.2ml

converting it to two significant figures

= 4200ml

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3 years ago
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