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kicyunya [14]
4 years ago
13

Combine the like terms to create an equivalent expression: --k+3k

Mathematics
2 answers:
mrs_skeptik [129]4 years ago
7 0

Answer:

the answer is 2k

Step-by-step explanation:

iragen [17]4 years ago
4 0

Answer:

idk but add me on sc at stephen.huston

Step-by-step explanation:

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Given Angle 1 = Angle 2,<br> find x.
drek231 [11]

Answer:

x = 6

Step-by-step explanation:

Given ∠ 1 = ∠ 2 then the segment is an angle bisector and the ratios of sides to base are equal, that is

\frac{3}{x-4} = \frac{x}{4} ( cross-  multiply )

x(x - 4) = 12 ← distribute left side

x² - 4x = 12 ( subtract 12 from both sides )

x² - 4x - 12 = 0 ← in standard form

(x - 6)(x + 2) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 6 = 0 ⇒ x = 6

x + 2 = 0 ⇒ x = - 2

However, x > 0 , thus x = 6

8 0
4 years ago
4/3 of 21, 2/3 of 21
nikdorinn [45]

of means multiply

4/3 x 21/1

= 84/3

= 28

2/3 x 21/1

=42/3

= 14

3 0
4 years ago
24 POINTS <br> Which table shows a proportional relationship between x and y?
Art [367]

first one is the correct answer


proportional relationship between x and y = 2: 1

3 0
4 years ago
The path of a projectile launched from a 16-ft-tall tower is modeled by the equation y = −16t2 + 64t +16. What is the maximum he
Aleks04 [339]

Answer:

<h3>80 feet</h3>

Step-by-step explanation:

Given the path of a projectile launched from a 16-ft-tall tower modeled by the equation y = −16t^2 + 64t +16

h is the maximum height reached

t is in seconds

The velocity of the projectile at its maximum height is zero;

velocity v = dy/dt

v = -32t + 64

Since v = 0 at maximum height

0 = -32t + 64

32t = 64

t = 2secs

Substitute t = 2secs into the equation of the height to get the maximum height.

y = −16t^2 + 64t +16

at t = 2secs

y = −16(2)^2 + 64(2) +16

y = -64 + 128 + 16

y = 64+16

y = 80 feet

Hence the maximum height, in feet, reached by the projectile is 80 feet

5 0
3 years ago
If tan 0= 1.3 what if the value of cot 90
Nimfa-mama [501]

Answer: 0

Explanation is on the picture

5 0
4 years ago
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