Answer:
15944.6 sec
Explanation:
d = distance of Pluto from earth = 32 AU = 32 x 1.496 x 10¹¹ m
v = speed of light = 1.08 x 10⁹ km/hr = ( 1.08 x 10⁹) (0.278) m/s
t = time taken for the communication to reach from probe to earth = ?
Using the equation
d = v t
Inserting the values given
32 x 1.496 x 10¹¹ = (( 1.08 x 10⁹) (0.278)) t
t = 15944.6 sec
t = 1.6 x 10⁴ sec
Answer:
méthode if séparation muddy water
Answer:
0.8 seconds
Explanation:
F=ma
Let x be the seconds the force is applied.
m = 20kg
F = 50 Newtons (kg*m/sec^2)
acceleration, a, is provided for x seconds to increase the speed from 1 m/s to 3 m/s, an increase of 2m/s
Let's calculate the acceleration of the cart:
F=ma
(50 kg*m/s^2) = (20kg)*a
a = 2.5 m/s^2
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The acceleration is 2.5 m/s^2. The cart increases speed by 2.5 m/s every second.
We want the number of seconds it takes to add 2.0 m/sec to the speed:
(2.5 m/s^2)*x = 2.0 m/s
x = (2.0/2.5) sec
x = 0.8 seconds
