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kaheart [24]
3 years ago
14

Between ball B and ball C, ball ____ has LESS potential energy because ___

Physics
1 answer:
Citrus2011 [14]3 years ago
8 0

Answer: b

Explanation:

Ec= (1/2)m × v^2

By the formula, you can see that the bigger the mass, the bigger the Cinetic Energy.

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Electromagnet Criteria Criteria Design 1 - iron nail, switch, 75 cm wire cut into 3 pieces, battery Design 2 - iron nail, 75 cm
Natali5045456 [20]

i came here for the answer lol.

3 0
3 years ago
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A cannon is fired from a castle wall at some unknown height above the ground. The cannonball leaves the cannon with speed 30.0m/
Sauron [17]

Answer:

Part a)

t = 3.85 s

Part b)

h = 72.67 m

Part C)

v_x = 25.98 m/s

v_y = 0

Part d)

In horizontal direction velocity will remain constant

v_x = 30 cos30 = 25.98 m/s

in vertical direction we have

v_y = -22.77 m/s

Explanation:

Part a)

Horizontal speed of the cannon

v = 30.0 m/s

angle of projection

\theta = 30^o

now we have

horizontal speed = v_x = vcos30 = 30 cos30 =25.98 m/s

vertical speed = v_y = vsin30 = 30 sin30 = 15 m/s

now the time taken by it to cover the distance 100 m from the wall

x = v_x t

100 = 25.98 t

t = 3.85 s

Part b)

Since it hits the ground in the same time

so the height of the castle is given as

h = \frac{1}{2}gt^2

h = \frac{1}{2}(9.81)(3.85^2)

h = 72.67 m

Part C)

At highest point of the projection

the vertical component of the velocity will become zero

so we will have

v_x = 25.98 m/s

v_y = 0

Part d)

In horizontal direction velocity will remain constant

so we have

v_x = 30 cos30 = 25.98 m/s

in vertical direction we have

v_y = v_i + at

v_y = 15 - 9.81(3.85)

v_y = -22.77 m/s

Part e)

8 0
3 years ago
Read 2 more answers
A boat takes off from the dock at 2.5m/s and speeds up at 4.2m/s2 for 6.0 seconds how far has the boat traveled
suter [353]

Answer:

The answer is "91 m"

Explanation:

v_0 = 2.5 \ \frac{m}{s}\\\\a = 4.2\ \frac{m}{s^2}\\\\t = 6.0\ s\\\\\Delta x=?

Using formula:

\Delta x = v_0 t +\frac{1}{2} at^2\\\\

      = 2.5 \times 6.0  +\frac{1}{2}  \times  4.2 \times 6.0^2\\\\= 90.6\  m \approx 91\ m

5 0
3 years ago
Where the sun's energy is produced
stellarik [79]
Well,

The sun's energy is produced mainly in the core, which has sufficient temperature to initiate nuclear fusion.

Hydrogen --> Deuterium --> Tritium --> Helium --> Beryllium? --> Carbon --> ? --> Silicon --> Iron/Nickel = Most massive stars<span />
6 0
3 years ago
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Two sinusoidal waves, which are identical except for a phase shift, travel along in the same direction. The wave equation of the
Y_Kistochka [10]

Answer:

two sinusoidal waves, which are identical except for a phase shift, travel along in the same direction. The wave equation of the resultant wave is yR (x, t) = 0.70 m sin⎛ ⎝3.00 m−1 x − 6.28 s−1 t + π/16 rad⎞ ⎠ . What are the angular frequency, wave number, amplitude, and phase shift of the individual waves?

ω = 6.28 s − 1 ,

k = 3.00 m− 1 ,

φ = π rad,

A R = 2 A cos (φ 2 ) ,

A = 0.37 m

Explanation:

y1 ( x , t ) = A sin( k x − ω t +φ ) ,

y 2 ( x , t ) = A sin ( k x − ω t ) .

from the principle of superposition which states that when two or more waves combine, there resultant wave is the algebriac sum of the individual waves

y1 ( x , t ) = A sin( k x − ω t +φ ) ,   is generaL form of thw wave eqaution

A=amplitude

k=angular wave number

ω=angular frequency

φ =phase constant

k=2π/lambda

ω=2π/T

yR (x, t) = 0.70 m sin{3.00 m−1 x − 6.28 s−1 t + π/16 rad}....................*

two waves superposed to give the above, assuming they are moving in the +x direction

y1 ( x , t ) = A sin( k x − ω t +φ ) , .....................1

y 2 ( x , t ) = A sin ( k x − ω t ) ...........................2

adding the two equation will give

A sin( k x − ω t +φ )+A sin ( k x − ω t ) .................3

A( sin( k x − ω t +φ )+ sin ( k x − ω t ) ),......................4

similar to the following trigonometry identity

sina+sinb=2cos(a-b)/2sin(a+b)/2

let a= ( k x − ω t

b=k x − ω t +φ )

y(x,t)=2Acos(φ/2)sin(k x − ω t +φ/2)

k=3m^-1

lambda=2π/k=2.09m

ω=6.28= T=2π/6.28

T=1s

φ/2=π/16

φ=π/8rad

amplitude

2Acos(φ/2)=0.70 m

A=0.7/2cos(π/8)

A=0.37 m

6 0
4 years ago
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