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3 years ago

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A diver who is 10.0 meters underwater experience has a pressure of 202 kPa. If the diver’s surface area is 1.50 meters squared,

with how much total force does the water push on the diver?

1 answer:

erastova [34]3 years ago

4 0

Force = 202,200 x 1.5 ms.q
Force = 303,000 newtons

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Unit of speed is derived unit why

madam [21]

Answer:

Explanation:

Therefore, the unit of speed is the meter per second, or m/s. The unit meter per second is called a derived unit, meaning that it is derived from the seven SI base units.

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3 years ago

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a ball drops some distance and loses 30 j of gravitational potential energy. do not ignore air resistance. how much kinetic ener

aniked [119]

Thus, more than 30 J of potential energy can be loosed by the ball. Thus, the gravitational potential energy of the ball is more than 30 J.

If there is no air resistance, the ball's potential energy is entirely transformed into kinetic energy. When air resistance is taken into account, a portion of the potential energy is used to overcome it. Thus, AU > AKE. In the current scenario, a ball gains 30 J of kinetic energy while falling and is treated as encountering air resistance. The energy that an object retains due to its position in relation to other objects, internal stresses, electric charge, or other factors is known as potential energy in physics. The potential energy will be transformed into kinetic energy if the stones fall. High on the tree, branches have the potential to fall, which gives them energy. Chemical potential energy exists in the food we eat.

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1 year ago

The focal length of a lens is inversely proportional to the quantity (n-1), where n is the index of refraction of the lens of th

Ainat [17]

Answer:

46.22 cm

Explanation:

The focal refraction, fr is given by

$fr = \frac {c}{(1.572 -1)} = \frac {c}{0 .572}$

The focal red light is given by

$fv = \frac {c}{(1.605 - 1)} = \frac {c}{0.605}$

$\frac {fv}{fr} = \frac {0.572}{0 .605} = 0.945455$

$\frac {1}{fr} = \frac{1}{image} + \frac {1}{object}$ and making fr the subject we obtain

$fr = \frac {image * object}{(image + object)} = \frac {24.00 * 55} {(24.0 + 55)} = 16.70886 cm$

fv = 0.945455* 16.70886 cm = 15.79747 cm

$image = \frac {object * f} {(object - f)} = \frac {15.79747 * 24.0}{(24.0 - 15.79747)} = 46.22222 cm$

Therefore, violet image is approximately 46.22 cm

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3 years ago

PE=30J, m=?, g=10m/s2, h=10m

OleMash [197]

Based on the given, this is probably a gravitational potential energy problem (PEgrav). The formula for PEgrav is:

PEgrav = mgh

Where:
m = mass (kg)
g = acceleration due to gravity
h = height (m)

With this formula you can derive the formula for your unknown, which is mass. First put in what you know and then solve for what you do not know.

$PEgrav=mgh$
$30J=m(10)(10[tex] \frac{30}{100} =m$ )[/tex]

Do operations that you can with what is given first.

$30J=m(100m)$

Transpose the 100 to the other side of the equation. Do not forget that when you transpose, you do the opposite operation.

$\frac{30}{100} =m$

m = 0.30kg

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3 years ago

A bug walking on the circular rim of a flower

Mekhanik [1.2K]

Given parameters;

Time taken to complete a lap = 8.667s

Radius of flower = 13.9cm

convert to SI unit of m, 100cm = 1m

13.9cm gives $\frac{13.9}{100}$ = 0.139m

Unknown = speed

To solve this problem, we need to first find the circumference of the flower.

Circumference of the circular flower = 2 π r

where r is the radius of the flower;

Circumference = 2 x 3.142 x 0.139 = 0.87m

Now to find the how fast the bug is travelling,

Speed = $\frac{distance}{time}$

Since the bug covered 1 lap, the distance is 0.87m

Now input the parameters and solve for speed;

Speed = $\frac{0.87}{8.667}$ = 0.1m/s

The bug is travelling at a speed of 0.1m/s

8 0

3 years ago