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soldi70 [24.7K]
3 years ago
9

Vector A has a magnitude of 30 units. Vector B is perpendicular to vector Aand has a magnitude of 40 units. What would the magni

tude of the resultant vector A + B be?
Physics
1 answer:
Fudgin [204]3 years ago
3 0

Answer:

|\vec A + \vec B| = 50 units

Explanation:

As we know that magnitude of two vectors is given as

|\vec A + \vec B| = \sqrt{A^2 + B^2 + 2AB cos\theta}

here we know that

A = magnitude of vector A

B = magnitude of vector B

\theta = angle between two vectors

so here we know that

A = 30 units

B = 40 units

angle = 90 degree

so we have

|\vec A + \vec B| = \sqrt{30^2 + 40^2 + 2(30)(40)cos90}

|\vec A + \vec B| = \sqrt{30^2 + 40^2}

|\vec A + \vec B| = 50 units

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