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____ [38]
3 years ago
6

Please help me with this problem.

Mathematics
1 answer:
MrRa [10]3 years ago
3 0

Step-by-step explanation:

cos(x + 45 \degree) + cos(x  -  45 \degree) =  \sqrt{2}  \\ cosx  \: cos45 \degree - sinx  \: sin45 \degree  \\ + cosx  \: cos45 \degree  + sinx  \: sin45 \degree  =  \sqrt{2}  \\ 2cosx  \: cos45 \degree =  \sqrt{2}  \\ 2cosx \times  \frac{1}{ \sqrt{2} }  =  \sqrt{2}  \\ 2cosx =  \sqrt{2}  \times  \sqrt{2}  \\ 2cosx = 2 \\ cosx =  \frac{2}{2}  \\ cosx = 1 \\ cosx = cos \: 0 \degree \\ \huge \red{ \boxed{ x = 0 \degree}} \\

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The clerk at the checkout counter earned $350 in 25 hours.
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Answer: 14 a hour

Step-by-step explanation:

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In ΔUVW, the measure of ∠W=90°, UV = 71 feet, and VW = 11 feet. Find the measure of ∠V to the nearest degree
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Step-by-step explanation:

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11(n-3)=-4<br><br> this is also for my friend
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Step-by-step explanation:

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Read 2 more answers
According to the National Bridge Inspection Standard (NBIS), public bridges over 20 feet in length must be inspected and rated e
slamgirl [31]

Answer:

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Step-by-step explanation:

For each bridge, there are only two possible outcomes. Either it has rating of 4 or below, or it does not. The probability of a bridge being rated 4 or below is independent from other bridges. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

For the year 2020, the engineers forecast that 9% of all major Denver bridges will have ratings of 4 or below.

This means that p = 0.09

Use the forecast to find the probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Either less than 4 have a rating of 4 or below, or at least 4 does. The sum of the probabilities of these events is 1.

So

P(X < 4) + P(X \geq 4) = 1

We want P(X \geq 4)

So

P(X \geq 4) = 1 - P(X < 4)

In which

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{12,0}.(0.09)^{0}.(0.91)^{12} = 0.3225

P(X = 1) = C_{12,1}.(0.09)^{1}.(0.91)^{11} = 0.3827

P(X = 2) = C_{12,2}.(0.09)^{2}.(0.91)^{10} = 0.2082

P(X = 3) = C_{12,3}.(0.09)^{3}.(0.91)^{9} = 0.0686

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.3225 + 0.3827 + 0.2082 + 0.0686 = 0.982

Finally

P(X \geq 4) = 1 - P(X < 4) = 1 - 0.982 = 0.0180

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

6 0
3 years ago
..........................help me pls?
Ludmilka [50]

Answer:

7x-7=y

Step-by-step explanation:

5x+7y=10

5x-10=10-7y-10

5x-10=-7y

(1/7)5x-10=7y(1/7)

5x/35-10/70=y

7x-7=y

<em>Sana</em><em> </em><em>maka</em><em>tulong</em><em> </em>

6 0
3 years ago
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