The solution is x = 8 and y = 2
<em><u>Solution:</u></em>
<em><u>Given are the system of equations</u></em>
2x + 3y = 22 -------- eqn 1
-2x + 5y = -6 ----- eqn 2
We can solve the system of equations by elimination method
<em><u>Add eqn 1 and eqn 2</u></em>
Eqn 1 + Eqn 2
2x + 3y -2x + 5y = 22 - 6
0x + 3y + 5y = 16
8y = 16
Divide both sides of equation by 8
<h3>y = 2</h3>
Substitute y = 2 in eqn 1
2x + 3(2) = 22
2x = 22 - 6
2x = 16
<h3>x = 8</h3>
Thus the solution is x = 8 and y = 2
Y-y1=m(x-x1)
y-(-2)=2/3(x-5)
y+2=2/3x-10/3
y=2/3x-10/3-2
=> y=2/3x-16/3
4.8 students take bus
not sure if right though
but hope it helps c:
I think 53.088 is the answer
Answer:
W1 = W2 = 50k Joules (assuming W1 and W2 have the same force constant, k)
W1 - W2 = 0
Step-by-step explanation:
Work done in stretching a spring is given by 1/2ke^2
Where, k is force constant and e is extension
e1 = 30cm - 20cm = 10cm
W1 = 1/2k(e1)^2 = 1/2×k×10^2 = 50k Joules
e2 = 40cm - 30cm = 10cm
W2 = 1/2k(e2)^2 = 1/2×k×10^2 = 50k Joules
W1 = W2 = 50k Joules provided W1 and W2 have equal force constant
Therefore, W1 - W2 = 0
