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saw5 [17]
3 years ago
6

You hear the engine roaring on a race car at the starting line. Predict the changes in the sound as the race starts and the car

approaches the camera. A) The sound of the engine will get louder and the pitch lower. Eliminate B) The sound of the engine will get louder and the pitch higher. C) The sound is determined by the car and it will not change in any way. D) The sound of the engine will get louder but the pitch will not change.
Physics
2 answers:
gogolik [260]3 years ago
4 0

B. The sound of the engine will get louder and the pitch higher.

Mariana [72]3 years ago
3 0

Answer: The correct option is B.

Explanation:

Doppler effect is the phenomenon in which there is an apparent change in the frequency when there is relative motion between source and listener.

When the source and the listener are approaching each other then the frequency increases. The loudness depends on the amplitude. The energy of the wave is directly proportional to the square of the amplitude.

In the given problem, the engine is roaring on a race car at the starting line. There is change in the sound as the race starts and the car approaches the camera.

Pitch depends on the frequency.

Therefore, the sound of the wave will get louder and the pitch will get higher.

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Calculate the acceleration using the formula acceleration = (final velocity - initial velocity) / time.
PtichkaEL [24]

Answer:

10 km/hr/s

Explanation:

The acceleration of an object is given by

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time

For the car in this problem:

u = 0

v=60 km/h

t = 6 s

Substituting in the equation,

a=\frac{60 km/h-0}{6s}=10 km/h/s

6 0
3 years ago
A turntable with a moment of inertia of 7.2 × − ⋅ rotates freely with an angular speed of 6.5 ⁄ . Riding on the rim of the turnt
irina1246 [14]

Answer:

turntable with a moment of inertia of 7.2 × − ⋅ rotates freely with an angular speed of 6.5 ⁄ . Riding on the rim of the turntable, 2 from the center, is a hamster. When the hamster walks to the center of the turntable, the angular speed of the turntable becomes ⁄. What is the mass of hamster?

Explanation:

6 0
2 years ago
A EXAMPLE OF WHEN BOTH PHYSICAL CHANGE AND CHEMICAL CHANGE OCCUR 3 EXAMPLES
kvasek [131]

Answer:

I know 1, that is in the case of a burning of a candle.

Explanation:

5 0
3 years ago
A light bulb emits light that travels uniformly in all directions. Detailed measurements show that at a distance of 56 m from th
vladimir1956 [14]

Complete question:

A light bulb emits light that travels uniformly in all directions. Detailed measurements show that at a distance of 56 m from the bulb, the amplitude of the electric field is 3.78 V/m. What is the average intensity of the light?

Answer:

The average intensity of the light is 0.02 W/m²

Explanation:

Given;

Amplitude of the electric field, E₀ = 3.78 V/m

The average intensity of the light is calculated as follows;

I_{avg} = \frac{c\epsilon_0 E_0^2}{2}

where;

I_{avg} is the average intensity of the light

c is speed of light = 3 x 10⁸ m/s

I_{avg} = \frac{(3\times 10^8)(8.85 \times 10^{-12}) (3.78)^2}{2} \\\\I_{avg} = 0.01897 \ W/m^2\\\\I_{avg} = 0.02 \ W/m^2

Therefore, the average intensity of the light is 0.02 W/m²

4 0
3 years ago
What is the energy in the spark produced by discharging the second capacitor? 1. The same as the discharge spark of the first ca
Nastasia [14]

Complete Question

The two isolated parallel plate capacitors be-  low, one with plate separation d and the other  with D > d, have the same plate area A and

are given the same charge Q.

What is the energy in the spark produced by discharging the second capacitor?

 1. The same as the discharge spark of the first capacitor

2. More energetic than the discharge spark of the first capacitor

3. Less energetic than the discharge spark of the first capacitor

Answer:

The correct option is 2

Explanation:

The formula for the energy stored in the capacitor is

             U = \frac{Q^2}{2C}

And generally the formula for finding the capacitance of a capacitor is

               C = \frac{\epsilon_oA}{d}

We can denote the capacitance of the first capacitor as C_1 = \frac{\epsilon_oA}{d}

          and   denote the capacitance of the second  capacitor as C_2 = \frac{\epsilon_oA}{D}

Looking at this formula we can see that C varies inversely with d            

as D > d it means that C_1 > C_2

                Since the charge is constant

                         U\  \alpha\ \frac{1}{C} i.e U varies inversely with C

           So C_1 > C_2   => U_2 >U_1

This means that the energy of spark would be more for capacitor two compared to capacitor one

The correct option is 2

6 0
3 years ago
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