Answer: ![0.69\°](https://tex.z-dn.net/?f=0.69%5C%C2%B0)
Explanation:
The angular diameter
of a spherical object is given by the following formula:
![\delta=2 sin^{-1}(\frac{d}{2D})](https://tex.z-dn.net/?f=%5Cdelta%3D2%20sin%5E%7B-1%7D%28%5Cfrac%7Bd%7D%7B2D%7D%29)
Where:
is the actual diameter
is the distance to the spherical object
Hence:
![\delta=2 sin^{-1}(\frac{16 m}{2(1338 m)})](https://tex.z-dn.net/?f=%5Cdelta%3D2%20sin%5E%7B-1%7D%28%5Cfrac%7B16%20m%7D%7B2%281338%20m%29%7D%29)
This is the angular diameter
No i took the test and the answer is actually homogenous mixture
Answer:
The force of gravity on a 700 kg satellite if its 10 km above Earth's surface is given by
=
= 3984378 m / ![s^{2}](https://tex.z-dn.net/?f=s%5E%7B2%7D)
Explanation:
The force of gravity on a 700 kg satellite if its 10 km above Earth's surface is given by
=
= 3984378 m / ![s^{2}](https://tex.z-dn.net/?f=s%5E%7B2%7D)
Answer:
a)5.88J
b)-5.88J
c)0.78m
d)0.24m
Explanation:
a) W by the block on spring is given by
W=
kx² =
(530)(0.149)² = 5.88 J
b) Workdone by the spring = - Workdone by the block = -5.88J
c) Taking x = 0 at the contact point we have U top = U bottom
So, mg
=
kx² - mgx
And,
= (
kx² - mgx
)/(mg) =
]/(0.645x9.8)
= 0.78m
d) Now, if the initial initial height of block is 3
= 3 x 0.78 = 2.34m
then,
kx² - mgx - mg
=0
(530)x² - [(0.645)(9.8)x] - [(0.645)(9.8)(2.34) = 0
265x² - 6.321x - 14.8 = 0
a=265
b=-6.321
c=-14.8
By using quadratic eq. formula, we'll have the roots
x= 0.24 or x=-0.225
Considering only positive root:
x= 0.24m (maximum compression of the spring)