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3 years ago

Help please! Step by steps

Mathematics

1 answer:

marin [14]3 years ago

7 0

Area of the square bottom = L x W = 5 x 5 = 25 square cm

Area of triangle = 1/2 x base x height = 1/2 x 5 x 6 = 15 square cm

Total area = 25 + 15 = 40 square cm.

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FIND the value of x. DO NOT POST ANY FILES

spayn [35]

Answer:

Step-by-step explanation:

The tangent segment is perpendicular to the diameter, so the triangle is a right triangle (not just based on its appearance). A property of circles is: a tangent is perpendicular to the radius drawn to the point of tangency.

In the right triangle, one leg has length 12.6, and the hypotenuse has length 21.

Apply the Pythagorean Theorem: (leg)^2 + (leg)^2 = (hypotenuse)^2

Oh, and the diameter has length 2x!

$(2x)^2+12.6^2=21^2\\\\4x^2+158.76=441\\\\4x^2=282.24\\\\x^2=70.56\\\\x=\sqrt{70.56}\\\\x=8.4$

7 0

2 years ago

Somebody pleaseee help :(

suter [353]

Answer:

answer is A fosha

Step-by-step explanation:

3 0

2 years ago

A. What would be the cost of the Standard Daily Rate plus Mileage plan?

Jobisdone [24]

Answer:

Part a) $\$190$

Part b) $\$315$

Part c) Standard Daily Rate plus Mileage plan

Step-by-step explanation:

Part a) What would be the cost of the Standard Daily Rate plus Mileage plan?

Let

y ----> the total cost

x ----> the number of kilometers

we have that

For a Luxury car

$y=70+0.30x$

For x=400 km

substitute

$y=70+0.30(400)$

$y=\$190$

Part b) What would be the cost of the Unlimited Mileage plan?

we know that

The Unlimited Mileage plan for a Luxury car is $105 per day (see the table)

The trip are three days

To find the total cost multiply $105 by 3

$3(\$105)=\$315$

Part c) Which is the better plan?

Compare

$\$190 < \$315$

therefore

For this trip the better plan is the Standard Daily Rate plus Mileage plan

7 0

3 years ago

1/2expand the equation 1/2(3+4t-10)=

Ivanshal [37]

$\frac{1}{2} (3 + 4t - 10)$

$\frac{3}{2} + \frac{4t}{2} - \frac{10}{2}$

$(\frac{3}{2} - \frac{10}{2}) + 2t$

$\frac{ - 7}{2} + 2t$

$- 3.5 + 2t$

8 0

2 years ago

An ant crawls at a rate of 216 ft per minute. At this rate, how long does it take the ant to crawl a distance of 515 ft? Enter y

quester [9]

216 ft per minute or 3.6 ft per second
515 divided by 216 is 2.38
it takes 2.38 minutes for the specified ant to crawl 515 feet

5 0

3 years ago