Question

The sum of a number and three times its reciprocal is 52/7. Find both possible answers

Answer 1

Answer:

x+3*1/x=52/7

7x^2/7x+21/7x=52x/7x

7x^2-52x+21=0

I solve this with the quadratic formula

Solution of ax^2+bx+c=0, a≠0 are :

x1= $\frac{-b+\sqrt{b^2-4ac}}{2a}$  and x2= $\frac{-b-\sqrt{b^2-4ac}}{2a}$

so a=7, b=-52,c=21

x1=$\frac{52+\sqrt{52^2-4*7*21} }{14}$= (52+46)/14=98/14=7

x2=(52-46)/14=6/14=3/7

Step-by-step explanation: