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Olegator [25]
4 years ago
10

PLEASE HELP!

Chemistry
1 answer:
11111nata11111 [884]4 years ago
6 0
The answer is A.......
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A 1.00 x 10^-10 M solution of chloric acid Please help me solve this to find pH and pOH​
Svetradugi [14.3K]

Answer: The pH of solution is 10.

The pOH of the solution is 4.

Explanation:

pH is the negative logarithm of concentration of hydrogen ion.

As given concentration of acidic solution is 1.00 \times 10^{-10} M. Therefore, pH of the solution is calculated as follows.

pH = -log [H^{+}]\\= -log (1.00 \times 10^{-10})\\= 10

The relation between pH and pOH is as follows.

pH + pOH = 14

pOH = 14 - pH

= 14 - 10

= 4

Thus, we an conclude that pH of solution is 10 and pOH of the solution is 4.

3 0
3 years ago
The fact that matter is not created or destroyed in any chemical or physical change is called the
BartSMP [9]

Answer:

Law of Conservation of Mass.

Is that Right?

8 0
3 years ago
Can colloidal suspensions be separated out by filtration? yes no
Genrish500 [490]
Yes the particles are larger than 10,000 Angstroms which allow it to be separated by filtration
6 0
4 years ago
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Hydrogen is diffusing through solid nickel. At a temperature of 358 K, the diffusivity is 1.16 x 10-8 cm2/s. At a temperature of
Lelu [443]

Answer:

Q_d=35881 J/mol

So the activation energy is 35881 J/mol.

Explanation:

Consider the following equations:

lnD_{1} =lnD_{o} -\frac{Q_{d} }{R*T_{1} }

lnD_{2} =lnD_{o} -\frac{Q_{d} }{R*T_{2} }

Solving the above two equation to find the Q_d in term of diffusivity and temperature we will get:

Q_{d}=-R*\frac{lnD_{1} -lnD_{2} }{\frac{1}{T_{1} }-\frac{1}{T_{2} }  }

where:

Q_d is the activation energy

D_1 is the diffusivity at T_1

D_2 is the diffusivity at T_2

Q_{d}=-8.31*\frac{ln1.16*10^-12 -ln1.05*10^-11 }{\frac{1}{358 }-\frac{1}{438 }  }

Q_d=35881 J/mol

So the activation energy is 35881 J/mol.

3 0
4 years ago
An experiment is carried out to observe the melting ice. Heat energy is supplied at a constant rate. The temperature of the ice
zhenek [66]

Answer:

If the ambient temperature around a piece of ice increases, the temperature of the ice will increase as well. However, this steady increase in temperature stops as soon as the ice reaches its melting point. At this point, the ice undergoes a change of state and turns into liquid water, and its temperature won't change until all of it has melted. You can test this with a simple experiment. Leave a cup of ice cubes in a hot car and monitor the temperature with a thermometer. You'll find that the icy water remains at a frosty 32 degrees Fahrenheit (0 degrees Celsius) until all of it has melted. When that happens, you'll notice a quick temperature rise as the water continues to absorb heat from the inside of the car.

7 0
3 years ago
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