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Charra [1.4K]
3 years ago
10

Consider the series ∑n=1[infinity]ln(n/(n+5)) Determine whether the series converges, and if it converges, determine its value.

Converges (y/n):
Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
5 0

It will diverge. Consider the Nth partial sum,

\displaystyle\sum_{n=1}^N\ln\frac n{n+5}=\sum_{n=1}^N(\ln n-\ln(n+5))

= (ln1 - ln6) + (ln2 - ln7) + (ln3 - ln8) + (ln4 - ln9) + (ln5 - ln10)

+ (ln6 - ln11) + (ln7 - ln12) + ...

+ (ln(N-5) - lnN) + (ln(N-4) - ln(N+1)) + (ln(N-3) - ln(N+2)) + (ln(N-2) - ln(N+3)) + (ln(N-1) - ln(N+4))

+ (lnN - ln(N+5))

Cancellation among terms leaves us with

= ln1 + ln2 + ln3 + ln4 + ln5 - ln(N+1) - ln(N+2) - ln(N+3) - ln(N+4) - ln(N+5)

We can write this as

\ln(1\cdot2\cdot3\cdot4\cdot5)-\ln((N+1)\cdot(N+2)\cdot(N+3)\cdot(N+4)\cdot(N+5))

\implies\displaystyle\sum_{n=1}^N\ln\frac n{n+5}=\ln\frac{120}{(N+5)(N+4)(N+3)(N+2)(N+1)}

Then as N\to\infty, the argument of the logarithm is 0, so the logarithm itself approaches -infinity. Then the limit of the series is non-zero, so it must diverge.

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