1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ira Lisetskai [31]
4 years ago
9

Compared to the atomic radius of a sodium atom, the atomic radius of a potassium atom is larger. The larger radius is primarily

a result of the potassium atom having:______________.
Chemistry
1 answer:
wlad13 [49]4 years ago
8 0

Answer:

an Additional shell

Explanation:

Potassium has an additional energy level when compared to sodium. This is due to an extra shell added. In the periodic table when you go down the group, the atomic radius increases due to increasing energy levels.

The atomic radius mean the distance from the center of the nucleus to the valance shell. it actually describes the size of the atom

You might be interested in
One of the main contaminants of a nuclear accident, such as that at Chernobyl, is strontium-90, which decays exponentially at an
igor_vitrenko [27]

Answer: a) %(C/Co) = (e^(-0.027t)) × 100

b) t1/2 = 25.67years

c) 5.872%

Explanation:

a) Radioactive reactions always follow a first order reaction dynamic

Let the initial concentration of Strontium-90 be Co and the concentration at any time be C

The rate of decay will be given as:

(dC/dt) = -KC (Minus sign because it's a rate of reduction)

The question provides K = 2.7% per year = 0.027/year

(dC/dt) = -0.027C

(dC/C) = -0.027dt

 ∫ (dC/C) = -0.027 ∫ dt 

Solving the two sides as definite integrals by integrating the left hand side from Co to C and the Right hand side from 0 to t.

We obtain

In (C/Co) = -0.027t

(C/Co) = (e^(-0.027t))

In percentage, %(C/Co) = (e^(-0.027t)) × 100

(Solved)

b) Half life of a first order reaction (t1/2) = (In 2)/K

K = 0.027/year

t1/2 = (In 2)/0.027 = 25.67 years

c) percentage that remains after 105years,

%(C/Co) = (e^(-0.027t)) × 100

t = 105

%(C/Co) = (e^(-0.027 × 105)) × 100 = 5.87%

8 0
3 years ago
The hydroboration of an alkene occurs in ___________ which places the boron of the borane on the ___________ carbon of the doubl
Nana76 [90]

Answer: The hydroboration of an alkene occurs in TWO CONCERTED STEP which places the boron of the borane on the LESS SUBSTITUTED carbon of the double bond. The oxidizing agent then acts as a nucleophile, attacking the electrophilic BORON and resulting in the placement of a hydroxyl group on the attached carbon. Thus, the major product of the hydroboration oxidation reaction DOES NOT follow Markovnikov's rule.

Explanation:

Hydroboration is defined as the process which allows boron to attain the octet structure. This involves a two steps pathway which leads to the production of alcohol.

--> The first step: this involves the initiation of the addittion of borane to the alkene and this proceeds as a concerted reaction because bond breaking and bond formation occurs at the same time.

--> The second step: this involves the addition of boron which DOES NOT follow Markovnikov's rule( that is, Anti Markovnikov addition of Boron). This is so because the boron adds to the less substituted carbon of the alkene, which then places the hydrogen on the more substituted carbon.

Note: The Markovnikov rule in organic chemistry states that in alkene addition reactions, the electron-rich component of the reagent adds to the carbon atom with fewer hydrogen atoms bonded to it, while the electron-deficient component adds to the carbon atom with more hydrogen atoms bonded to it.

8 0
3 years ago
Р<br> +<br> 02<br> =<br> P4O6 <br> balance the equation
sergejj [24]

To balance a chemical equation, both sides should have equal mass, or in other words both sides should have same number of atoms as to follow the conservation of mass rule.

P + O₂ = P₄O₆

LHS:

Number of Phosphorus atoms = 1 atom

Number of Oxygen atoms = 2 atoms

RHS:

Number of Phosphorous atoms = 4 atoms

Number of Oxygen atoms = 6 atoms

Also since P₄O₆ has the most number of atoms we will make the LHS equalize to P₄O₆.

Difference between Phosphorous atoms in LHS to RHS = 3

Since phosphorous is a monatomic we need 3 phosphorous atoms extra

Difference between Oxygen atoms is LHS to RHS = 4

But Oxygen is diatomic, so we need 4/2 = 2 Oxygen molecules

Now lets see if it is balanced

P + 3P + O₂ + 2O₂ -------> P₄O₆

               4P + 3O₂ ------>  P₄O₆

LHS:

Phosphorous atoms = 4 atoms

Oxygen atoms = 3 × 2 = 6 atoms

RHS:

Phosphorous atoms = 4 atoms

Oxygen atoms = 6 atoms

LHS = RHS

Therefore the balanced equation is 4P + 3O₂ =  P₄O₆

Happy to help :)

If you need more explanation or help in any other question, feel free to ask

3 0
3 years ago
. Consider the following 3 systems: a. A binary mixture with vapor-liquid equilibrium, both components are generally present in
Leona [35]
Offf kfff offf please thank me
7 0
3 years ago
Gold cylinder has a mass of 75 g and a specific heat of 0.129J/G degrees Celsius it is heated to 65°C and then put in 500 g of w
nadezda [96]
<h3>Answer:</h3>

89.88° C

<h3>Explanation:</h3>

<u>We are given;</u>

  • Mass of gold cylinder as 75 g
  • specific heat of gold is 0.129 J/g°C
  • Initial temperature of gold cylinder is 65°C
  • Mass of water is 500 g
  • Initial temperature of water is 90 °C

We are required to calculate the final temperature;

  • We know that Quantity of heat is given by the product of mass, specific heat capacity and change in temperature.
  • That is, Q = m × c × ΔT
<h3>Step 1: Calculate the quantity of heat absorbed by the Gold cylinder</h3>

Assuming the final temperature is X° C

Then; ΔT = (X-65)°C

Therefore;

Q = 75 g × 0.129 J/g°C × (X-65)°C

   = 9.675X - 628.875 Joules

<h3>Step 2: Calculate the quantity of heat released by water</h3>

Taking the final temperature as X° C

Change in temperature, ΔT = (90 - X)° C

Specific heat capacity of water is 4.184 J/g°C

Therefore;

Q = 500 g × 4.184 J/g°C × (90 - X)° C

  = 188,280 -2092X joules

<h3>Step 3: Calculate the final temperature, X°C</h3>

we know that the heat gained by gold cylinder is equal to the heat released by water.

9.675X - 628.875 Joules = 188,280 -2092X joules

2101.675 X = 188908.875

              X = 89.88° C

Thus, the final temperature is 89.88° C

3 0
3 years ago
Other questions:
  • Determine the temperature, volume, and quality of 1kg of H2O under the following conditions
    13·1 answer
  • Which step should be next in this procedure?.
    5·2 answers
  • Convert 4.03 x 10^22 atoms of Na to moles of Na
    11·1 answer
  • What is the mole for H2PO3
    10·1 answer
  • If a metal changes color over time from exposure to air what has likely occurred
    6·1 answer
  • How does an atom end up with an octet, if it loses all of the electrons in its valence shell
    7·1 answer
  • A 62.9 g sample of ground water is found to have a lead concentration of 13.97 ppm. Calculate the mass of lead in the sample in
    5·1 answer
  • What are the half-reactions for a galvanic cell with aluminum and gold electrodes?
    14·1 answer
  • What are the rows of the periodic table called?
    8·1 answer
  • Iron has two oxidation states +2 and + 3 there are two possible equations for the redox reaction
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!