Answer:
43.05 moles of Al needed to react with 28.7 moles of FeO.
Explanation:
Given data:
Moles of FeO = 28.7 mol
Moles of Al needed to react with FeO = ?
Solution:
Chemical equation:
2Al + 3FeO → 3Fe + Al₂O₃
Now we will compare the moles of Al with FeO.
FeO : Al
2 : 3
28.7 : 3/2×28.7 = 43.05 mol
Thus 43.05 moles of Al needed to react with 28.7 moles of FeO.
At room temperature, O2 is in gaseous state.
a gas has no definite volume or definite shape. It occupies volume of container and attains shape of container only.
Thus
It has no definite volume and takes the shape of its container.
Its particles move fast enough to overcome the attraction between them.: the gas molecules have minimum intermolecular interactions and have high kinetic energy.
It has more energy than it would at a cooler temperature: the kinetic energy of gas molecules increases with increase in temperature. Thus the energy increases with temperature and decreases with decrease in temperature.
Protons= 12, Electrons= 12, neutrons= 12
Answer: 19.8 l
Explanation:
1) Chemical equation:
2Ca + O₂ → 2CaO
2) Mole ratios: 2 mol Ca : 1 mol O₂ : 2 mol CaO
3) Convert 35.4 g of Ca to moles:
n = mass in grams / molar mass = 35.4 g / 40.1 g/mol = 0.883 mol
4) Volume proportion: 1 mol of gas at STP = 22.4 l
1 mol at STP 0.883 mol at STP
--------------------- = ------------------------------
22.4 l x
⇒ x = 0.883 mol × 22.4 l / 1 mol = 19.8 l ← answer
