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3 years ago

Which of the following would be a warning sign that information about a weight loss medication is not reliable science?

Chemistry

2 answers:

Nat2105 [25]3 years ago

8 0

I think the best option is C

Hope this helps

docker41 [41]3 years ago

3 0

The correct answer is B. The scientists and all test subjects involved in the investigation work for the company that sells the medication.

Explanation:

In science, a medication, product or similar is only considered as reliable if it has been tested following the scientific method and if there are not interests that can affect the process or the result. This commonly implies, using the medication in a test group and compare the results to a control group that does not use medication, prove there was a positive effect on the test group people from the control group did not have and also being able to replicate the study which means this can be applied with more groups and the results would be consistent. However, that scientist and test subjects work for the company that sells the medication is not a factor that contributes to reliability and indeed is a warning sign because due to their interest in selling the medication they can alter or influence testing to sell the medication and therefore this is not reliable.

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pH is the hydrogen ion concentration and pOH is the hydroxide ion concentration in the solution. pH KOH is 12.73, pOH KOH is 2.24 and pH NaCl is 7.

pH is the negative log of the hydrogen ion concentration and pOH is the negative log of the hydroxide ion concentration.

The relation between the pH and pOH can be given as, $\rm pOH = 14 - pH$

The pH of KOH can be calculated by the formula,

$\rm pH = \rm -log [H^{+}]$

In the first case, the concentration of the KOH is $1. 87 \times 10^{-13}\;\rm M$

Substituting values in the equation:

$\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 87 \times 10^{-13}\;\rm M ]\\\\&= 12.73\end{aligned}$

Hence, the pH of KOH is 12.73.

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pOH of KOH can be calculated by the formula,

$\rm pOH = \rm -log [OH^{-}]$

The hydroxide concentration of the KOH solution is $5. 81 \times 10^{-3}\;\rm M$

Substituting value in the equation:

$\begin{aligned} \rm pOH &= \rm -log [OH^{-}]\\\\&= \rm -log [5. 81 \times 10^{-3}\;\rm M ]\\\\&= 2.24 \end{aligned}$

Hence, the pOH of KOH is 2.24

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The pH of NaCl can be calculated by the formula,

$\rm pH = \rm -log [H^{+}]$

In the third case, the concentration of the NaCl is $1. 00\times 10^{-7}\;\rm M$

Substituting values in the equation:

$\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 00 \times 10^{-7}\;\rm M ]\\\\&= 7 \end{aligned}$

Hence, the pH of KOH is 7.0.

Therefore, KOH is basic and NaCl is approximately neutral.

Learn more about pH and pOH here:

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