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Elena L [17]
3 years ago
5

Which formula equation represents the burning of sulfur to produce sulfur dioxide?

Chemistry
2 answers:
Leni [432]3 years ago
5 0

Answer:

S(s) + O2(g) --> SO2(g)

Upper S (s) plus upper O subscript 2 (g) right arrow with delta above upper S upper O subscript 2 (g).

Explanation:

The reaction is given as;

Sulfur + oxygen --> Sulphur dioxide

Sulphur = S

Oxygen = O2

Sulfur dioxide = SO2

So we have;

S(s) + O2(g) --> SO2(g)

The crrect option is option A. Upper S (s) plus upper O subscript 2 (g) right arrow with delta above upper S upper O subscript 2 (g).

brilliants [131]3 years ago
5 0

Answer:

Options a, b and c.

Explanation:

The reaction of production of SO₂ (sulfur dioxide) is the following:

S + O → SO₂(g)    (1)

The SO₂ can be produced by the combustion of materials that contain sulfur, thus the other alternative reactions of formation of SO₂ are the followings:

2H₂S + 3O₂ → 2H₂O + 2SO₂     (2)            

4FeS₂ + 11O₂ → 2Fe₂O₃ + 8SO₂    (3)            

The reaction (1) is exothermic, it produces temperatures of 1000–1600 °C.

A combination of the reactions (2) and (3) can be found in volcanic eruptions.

Therefore, the correct options are a, b and c. We discard the option d because that reaction produces SO₃ instead of SO₂.

I hope it helps you!

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Margarita [4]

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3. Kinetic Energy is the amount of energy a object has when it's in motion or moving.

4. Kinetic Energy is it's highest in the third stage after it's gone down the tract and potential energy fully decreased and it's at zero.

Remember that potential energy is stored energy so when a object is not moving in this case the roller coaster isn't moving on the first stage when its bout to go down the roller coaster. Kinetic energy is the amount of energy a object has when it's in motion so in this case the third stage would have the highest example of Kinetic energy because it's fully in motion and has no potential energy.

4 0
3 years ago
In an extraction experiment similar to your expt. 4, you attempt to separate 2-naphthol from cyclohexane, both of which are diss
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Answer:

[a]. 108 mL.

[b].

1. use HCL in washing for the neutralization of NaOH.

2. Wash with water.

3. make use of MgSO4 to remove water traces.

4. Evaporate to get the pure cyclohexane

Explanation:

The chemical equation for the reaction between 2-naphthol and Sodium hydroxide is given below as:

C₁₀H₈O + NaOH --------------------------------------------------> C10H7O⁻ Na⁺ + H₂O.

The C10H7O⁻ Na⁺ is  the aqueous phase.

The molarity of Sodium Hydroxide is = [ (mass of sodium hydroxide ) ÷ molar mass sodium  hydroxide × volume] × 1000.

The molarity of sodium hydroxide = [ (5/40) × 100] × 1000 =  1.25 M.

The number of moles of 2-naphthol = mass / molar mass =  20 / 144.17 = 0.138 moles.

Recall that, the formula for the number of moles = concentration × volume. Therefore, the volume of sodium hydroxide is given below as:

Volume of sodium hydroxide = the number of moles of sodium hydroxide ÷  concentration of sodium hydroxide = 0.138 ÷  1.25 = 0.108L = 108 mL.

In order to efficiently isolate relatively pure cyclohexane from the ether layer, the following process must be followed:

1. use HCL in washing for the neutralization of NaOH.

2. Wash with water.

3. make use of MgSO4 to remove water traces.

4. Evaporate to get the pure cyclohexane

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3 years ago
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sweet [91]

Answer:

CH4

Explanation:

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8 0
3 years ago
Difference between clinical and laboratory thermometer
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Answer:

1)clinical thermometer has temperature range 35 to 42degree celcius where labouratery thermometer has -10 to 110 degree celcius.

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4 years ago
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To interconvert the concentration units molality (m) and mass percent, you must also know the density of the solution. A) True B
uranmaximum [27]

Answer:

The correct answer is option false.

Explanation:

Molality of the solution defined as moles of substance present in 1 kilogram of   solvent.

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Molality=\frac{Moles}{\text{Mass of solvent(kg)}}

Mass of percent (w/w%) of the solution is defined as amount of solute present in 100 grams of solution.

(w/w\%)_=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100

So, if want to inter-convert molality into mass percent we can do that without knowing density of solution.

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7 0
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