Evaluate. write in simplest form. for 6 -b/3a a = 10, b = –9
1 answer:
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Neato
assuming you mean
remember
in form
a is leading coficient
(h,k) is vertex
k will be the minimum or max value of the function
if a is positive, then the parabola opens up and k is minimum
if a is negative, then the parabola opens down and k is max
given
a is negative
the parabola opens down and k is the max value
it is -3
the max value is -3, which occors at x=2
g(2)=-3 is max
assuming you mean
remember
in form
a is leading coficient
(h,k) is vertex
k will be the minimum or max value of the function
if a is positive, then the parabola opens up and k is minimum
if a is negative, then the parabola opens down and k is max
given
a is negative
the parabola opens down and k is the max value
it is -3
the max value is -3, which occors at x=2
g(2)=-3 is max
Answer:
m∠1 = 107 degrees
m∠2 = 73 degrees
Step-by-step explanation:
1. ∠1 and the angle with 107 degrees are corresponding angles, which are located in the same relative position. They're congruent in measures, so m∠1 = 107 degrees.
2. ∠1 and ∠2 are a linear pair, meaning their angle measures add up to 180 degrees. Given m∠1 = 107 degrees, we just have to subtract 107 from 180 to get m∠2.
Therefore, m∠2 = 73 degrees.