Perform the subtraction 33.5

NEED ASAP Which line is parallel to the line y=4x-2?

Umnica [9.8K]

Answer:

y = 4x + 1

Step-by-step explanation:

Given the equation y = 4x - 2, we need to find the equation parallel to this line. Note that for two equations to be parallel to each other, the must have the same slope

Standard form of an equation is y = mx + b

Compare;

mx = 4x

m = 4

Since the slope of the given equation is 4, the required equation must also have a slope of 4

Since we are not given an option, we can assume any equation with a slope of 4

y = 4x + 1 will be parallel to the given equation since they both have the same slope

Note that the equation can be different so far they have the slope of 4

8 0

2 years ago

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - α)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of z for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0

2 years ago

The value of a car is $20,000. It loses 10.7% of its value every year . Find the approximate monthly decrease in value . Round y

jenyasd209 [6]

Answer:

$178.3

Step-by-step explanation:

The value of a car is $20,000

The car loses 10.7% of its value yearly

Since there are 12 months in a year then 10.7% can be represented as

10.7%/12

= 0.8916%

Therefore the approximate monthly decrease in value can be calculated as follows

= $20,000×0.8916/100

= $20,000×0.008916

= $178.3

Hence the approximate monthly decrease in value is $178.3

7 0

2 years ago

The hypotenuse of a right triangle is 14 centimeters long. One of the legs of the triangle is 6 centimeters. What is the length

BartSMP [9]

Answer: 12.65 cm

Step-by-step explanation:

Use the Pythagoras theorem,

a^2 + b^2= c^2

You are given the hypotenuse , which is c and another leg which is either a or b, does not particularly matter- rearrange to find the missing length

c^2 - b^2 = a^2

14^2 - 6^2 = 160

Square root 160 to find the missing length

12.65

Hope this helped :)

5 0

3 years ago

Write the phrase as an expression. Then evaluate the expression when x = 5.

Nadusha1986 [10]

Answer:

6 + 8x

46

Step-by-step explanation:

1. Write the expression

6 + 8x

2. Plug in 5 for x

6 + 8(5) → 6 + 40 = 46

6 0

2 years ago

Perform the subtraction 33.5 - 6.02