Answer:
Pressure in the oil is 54.89 Mpa
Explanation:
Pressure is the ration of force applied to the perpendicular area. Pressure is uniform and perpendicular to surface.
Step1
Given:
Diameter of the piston is 30 mm.
Force exert is 38.8 kN.
Calculation:
Step2
Expression for pressure in the oil is expressed as follows:
Here, P is the pressure, A is the normal surface area and F is the exerted force on the piston.
Substitute the values in the above equation as follows:
pa.
Or,
P = 54.89 Mpa.
Thus, the pressure in the oil is 54.89 Mpa.
Answer:
A
Explanation:
A because you are continuing to keep moving and thinking.
Answer:
Polymers are the naturally occurring or synthetic macromolecules that are composed of repeating subunits, called monomers.
The three main classes of polymers are: thermoplastic, thermosetting, and the elastomers.
Thermoplastic polymers have linear bonding. These polymers can be melted again and thus can recycled.
Thermosetting polymers have cross-linked bonding. These polymers decompose when heated and thus can not be remelted and recycled.
Elastomers have linear bonding with some cross-linking. These polymers extreme elastic extensibility and thus can revert back to its original shape after deformation, without causing any permanent damage.
Answer:
1) the final temperature is T2 = 876.76°C
2) the final volume is V2 = 24.14 cm³
Explanation:
We can model the gas behaviour as an ideal gas, then
P*V=n*R*T
since the gas is rapidly compressed and the thermal conductivity of a gas is low a we can assume that there is an insignificant heat transfer in that time, therefore for adiabatic conditions:
P*V^k = constant = C, k= adiabatic coefficient for air = 1.4
then the work will be
W = ∫ P dV = ∫ C*V^(-k) dV = C*[((V2^(-k+1)-V1^(-k+1)]/( -k +1) = (P2*V2 - P1*V1)/(1-k)= nR(T2-T1)/(1-k) = (P1*V1/T1)*(T2-T1)/(1-k)
W = (P1*V1/T1)*(T2-T1)/(1-k)
T2 = (1-k)W* T1/(P1*V1) +T1
replacing values (W=-450 J since it is the work done by the gas to the piston)
T2 = (1-1.4)*(-450J) *308K/(101325 Pa*650*10^-6 m³) + 308 K= 1149.76 K = 876.76°C
the final volume is
TV^(k-1)= constant
therefore
T2/T1= (V2/V1)^(1-k)
V2 = V1* (T2/T1)^(1/(1-k)) = 650 cm³ * (1149.76K/308K)^(1/(1-1.4)) = 24.14 cm³
Answer:
Volume=2160 m^3
Depth=2160/A m
Explanation:
Detailed explanation of the answer is given in the attached files.