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n200080 [17]
2 years ago
12

A pump transfers water from a lake to a reservoir, which is located 29.2 m above the lake, at a rate of 11.5 L/s. Determine the

amount of power (in kW) required to pump water from the lake to the reservoir.
Engineering
1 answer:
Greeley [361]2 years ago
8 0

Answer:

P=3290.84KW

Explanation:

From the question we are told that:

Heighth=29.2m

Rate Q=11.5L/s=>11.5*10^{-3}

Generally the equation for Power is mathematically given by

P=\rho*g*Q*h

P=1000*9.81*11.5*10^{-3}*29.2

P=3290.84KW

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Oduvanchick [21]

Answer and Explanation:

The crack formation growth that takes place in an environment corrosive.

Stress corrosion cracks can be defined as the spontaneous failures of the metal alloy as a result of the combined action of corrosion and high tensile stress.

Some of the characteristic features of stress corrosion cracks are:

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3 years ago
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Answer:

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7 0
2 years ago
we want to make a schottky diode on one surface of an n-type semiconductor, and an ohmic contact on the other side. the electron
RoseWind [281]

Answer:

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7 0
3 years ago
An inductor has a 50.0-Ω reactance when connected to a 60.0-Hz source. The inductor is removed and then connected to a 45.0-Hz s
nignag [31]

Given:

X_{L} = 50.0 \ohm

frequency, f = 60.0 Hz

frequency, f' = 45.0 Hz

V_rms} = 85.0 V

Solution:

To calculate max current in inductor, I_{L(max):

At f = 60.0 Hz

X_{L} = 2\pi fL

50.0 = 2\pi\times 60.0\times L

L = 0.1326 H

Now, reactance X_{L} at f' = 45.0 Hz:

X'_{L} = 2\pi f'L

X'_{L} = 2\pi\times 45.0\times 0.13263 = 37.5\ohm

Now, I_{L(max) is given by:

I_{L(max) = \sqrt {\frac{2V_{rms}}{X'_{L}}}

I_{L(max) = \sqrt {\frac{2\times 85.0}{37.5}} = 2.13 A

Therefore,  max current in the inductor, I_{L(max) = 2.13 A

7 0
3 years ago
A student engineer is given a summer job to find the drag force on a new unmaned aerial vehicle that travels at a cruising speed
yan [13]

Answer:

b. 1232.08 km/hr

c. 1.02 kn

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See attachment for the remaining.

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