Answer:
Rate of Heat Loss = 336 W
Explanation:
First, we will find the surface area of the cylinder that is modelled as the man:

where,
r = radius of cylinder = 30 cm/2 = 15 cm = 0.15 m
l = length of cylinder = 170 cm = 1.7 m
Therefore,

Now, we will calculate the rate of heat loss:

where,
h = convective heat tranfer coefficient = 15 W/m²K
ΔT = Temperature difference = 34°C - 20°C = 14°C
Therefore,

<u>Rate of Heat Loss = 336 W</u>
Answer:
Tc = 424.85 K
Explanation:
Given that,





HEAT FLOW Q is

= 47123.88 w per unit length of rod
volumetric heat rate





= 424.85 K
Answer:
26 lbf
Explanation:
The mass of the satellite is the same regardless of where it is.
The weight however, depends on the acceleration of gravity.
The universal gravitation equation:
g = G * M / d^2
Where
G: universal gravitation constant (6.67*10^-11 m^3/(kg*s))
M: mass of the body causing the gravitational field (mass of Earth = 6*10^24 kg)
d: distance to that body
15000 miles = 24140 km
The distance is to the center of Earth.
Earth radius = 6371 km
Then:
d = 24140 + 6371 = 30511 km
g = 6.67*10^-11 * 6*10^24 / 30511000^2 = 0.43 m/s^2
Then we calculate the weight:
w = m * a
w = 270 * 0.43 = 116 N
116 N is 26 lbf