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denpristay [2]
3 years ago
10

What is the force exerted on a moving charge of -2.0 C at a 20° angle through a magnetic field of 3.0 x 10-4T with a

Physics
1 answer:
Scrat [10]3 years ago
8 0

Answer:

1026 N

Explanation:

Force on a moving charge in a magnetic field is given by

F= qvB Sinθ

F = 2 x 5 x 10^6 x 3 x 10-4 x Sin (20)

F = 1026 N

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3 years ago
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3 years ago
Assume that the loop is initially positioned at θ=30∘θ=30∘ and the current flowing into the loop is 0.500 AA . If the magnitude
labwork [276]

Answer:\tau=1.03\times 10^{-4}\ N-m

Torque,

Explanation:

Given that,

The loop is positioned at an angle of 30 degrees.

Current in the loop, I = 0.5 A

The magnitude of the magnetic field is 0.300 T, B = 0.3 T

We need to find the net torque about the vertical axis of the current loop due to the interaction of the current with the magnetic field. We know that the torque is given by :

\tau=NIAB\ \sin\theta

Let us assume that, A=0.0008\ m^2

\theta is the angle between normal and the magnetic field, \theta=90^{\circ}-30^{\circ}=60^{\circ}

Torque is given by :

\tau=1\times 0.5\ A\times 0.0008\ m^2\times 0.3\ T\ \sin(60)\\\\\tau=1.03\times 10^{-4}\ N-m

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3 years ago
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