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maria [59]
3 years ago
12

Which type of ladder has flat steps, hinged back, self-supporting, and non-adjustable?

Physics
1 answer:
il63 [147K]3 years ago
5 0

Answer:  Step Ladders

In general ladders are with inclined or vertical set of steps or rungs between two upright lengths of metal or wood. Ladders used for climbing up and down.

<u>Step ladders :</u>

It is a self supporting portable ladder, most commonly used in industries.  Self-supporting means it does not need any support to lean.  So this ladder can be used any where in the rooms. For example middle of the room  where support is not available. Also this ladder is non-adjustable flat steps and hinged back.  

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Gradpoint? The answer is B
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3 years ago
Which of the following would increase the amount of electricity generated by a wind turbine
kotykmax [81]

Higher wind speeds would increase the amount of electricity generated by a wind turbine.

<h3>What is a power plant?</h3>

A power plant is an industrial structure that generates electricity. The majority of power plants are linked to the electrical grid.

Stronger winds produce greater power because they enable the blades to revolve more quickly. Greater mechanical and electrical power from the generator result from faster spinning.

Hence, higher wind speeds would increase the amount of electricity generated by a wind turbine.

To learn more about the power plant, refer to the link;

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8 0
2 years ago
How does the design of rutherfords experiment show what he was trying to find out
gizmo_the_mogwai [7]
The  design of rutherfords experiment show what he was trying to find out is by detect charged particles. He shot positively charged alpha particles at foil containing gold atoms, what they did showed what was in them neutrons etc Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
3 0
3 years ago
Nellie pulls on a 10kg wagon with a constant horizontal force of 30N. If there are no other horizontal gorces what is the wagons
kicyunya [14]

Answer:

a=3m/s^2

Explanation:

If we have a net force F acting on a body of mass m it will experiment an acceleration a. Newton's 2nd Law gives us the relation between these quantities: F=ma.

In our case, we want to calculate the acceleration, so we write:

a=\frac{F}{m}

With the values we have we get:

a=\frac{30N}{10Kg}=3m/s^2

3 0
3 years ago
A 0.5 kg block slides down a frictionless semicircular track from a height, h, and collides with a second 1.5 kg block at the bo
Ede4ka [16]

Answer:

h' = 0.062\cdot h

Explanation:

The speed of the 0.5 kg block just before the collision is found by the Principle of Energy Conservation:

U_{g} = K

m\cdot g \cdot h = \frac{1}{2}\cdot m \cdot v^{2}

v = \sqrt{2\cdot g \cdot h}

v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot h}

v \approx 4.429\cdot \sqrt{h}

Knowing that collision is inelastic, the speed just after the collision is determined with the help of the Principle of Momentum Conservation:

(0.5\,kg) \cdot (4.429\cdot \sqrt{h}) = (2\,kg)\cdot v

v = 1.107\cdot \sqrt{h}

Lastly, the height reached by the two blocks is:

K = U_{g}

\frac{1}{2}\cdot m \cdot v^{2} = m\cdot g \cdot h'

h' = \frac{v^{2}}{2\cdot g}

h' = \frac{(1.107\cdot \sqrt{h})^{2}}{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)}

h' = 0.062\cdot h

3 0
3 years ago
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