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wlad13 [49]
3 years ago
9

A mass m on a spring with a spring constant k is in simple harmonic motion with a period T. If the same mass is hung from a spri

ng with a spring constant of 3k, the period of the motion will be _______.
Physics
1 answer:
inessss [21]3 years ago
5 0

Answer:

d) decreased by a factor of the square root of 3

Explanation:

Data provided in the question

Mass = M on a spring

Spring constant = k

Period = T

Spring constant = 3k in the case when the same mass is hung

Based on the above information, the period of the motion is

As we know that

T = 2\times Pi\times \sqrt{\frac{m}{k}}

Based on this, there is a decrease by a factor of the square root of 3

hence, the correct option is d.

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a force that is able to act at a distance

Explanation:

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Explanation:

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Assume that the amplifiers on the stage operate at a combined power of 5,000 Watts, and that 80% of this is converted to sound.
rusak2 [61]

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0.04

Explanation:

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3 years ago
A ray of light incident in air strikes a rectangular glass block of refractive index 1.50, at an angle of incidence of 45°. Calc
balandron [24]

Answer:

Approximately 28^{\circ}.

Explanation:

The refractive index of the air n_{\text{air}} is approximately 1.00.

Let n_\text{glass} denote the refractive index of the glass block, and let \theta _{\text{glass}} denote the angle of refraction in the glass. Let \theta_\text{air} denote the angle at which the light enters the glass block from the air.

By Snell's Law:

n_{\text{glass}} \, \sin(\theta_{\text{glass}}) = n_{\text{air}} \, \sin(\theta_{\text{air}}).

Rearrange the Snell's Law equation to obtain:

\begin{aligned} \sin(\theta_{\text{glass}}) &= \frac{n_{\text{air}} \, \sin(\theta_{\text{air}})}{n_{\text{glass}}} \\ &= \frac{(1.00)\, (\sin(45^{\circ}))}{1.50} \\ &\approx 0.471\end{aligned}.

Hence:

\begin{aligned} \theta_{\text{glass}} &= \arcsin (0.471) \approx 28^{\circ}\end{aligned}.

In other words, the angle of refraction in the glass would be approximately 28^{\circ}.

7 0
2 years ago
Joanne drives her car at a speed of 20 m/s. when she applied her breaks, a frictional force of 2000 N brought her car to a compl
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Answer:

A) 1000 kg

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0 = 20 + (a)(10)

a = -2.0 m/s^2

F = ma

2000 = (m)(2)

m = 1000 kg

8 0
1 year ago
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