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wlad13 [49]
3 years ago
9

A mass m on a spring with a spring constant k is in simple harmonic motion with a period T. If the same mass is hung from a spri

ng with a spring constant of 3k, the period of the motion will be _______.
Physics
1 answer:
inessss [21]3 years ago
5 0

Answer:

d) decreased by a factor of the square root of 3

Explanation:

Data provided in the question

Mass = M on a spring

Spring constant = k

Period = T

Spring constant = 3k in the case when the same mass is hung

Based on the above information, the period of the motion is

As we know that

T = 2\times Pi\times \sqrt{\frac{m}{k}}

Based on this, there is a decrease by a factor of the square root of 3

hence, the correct option is d.

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________ is the stress caused by forces that slip or slide one part of a material against another. a) Bending b) Shear c) Compre
jenyasd209 [6]
The best answer to fill in the blank would be B) Shear because shear stress is the process of where the composition of an object changes by sliding forces and so because of this, its a deformity.
8 0
4 years ago
A tortoise and hare start from rest and have a race. As the race begins, both accelerate forward. The hare accelerates uniformly
Mnenie [13.5K]

Answer:

The acceleration of the hare once it begins to slow down is -0.68 m/s²

The acceleration of the tortoise is 0.28 m/s²

Explanation:

The equations that describe the position and velocity of the hare and the tortoise are the following:

x = x0 + v0 · t + 1/2 · a · t²

v = v0 + a · t

Where:

x = position at time t

x0 = initial position

v0 = initial velocity

t = time

a = acceleration

v = velocity at time t

To find the acceleration of the hare once it begins to slow down, we have to find how much time the hare traveled during the deceleration and what was its initial speed.

First, the hare moves with constant acceleration for 4.7 s. Then, its velocity at  t = 4.7 s will be:

v = v0 + a · t    (v0 = 0 because the hare starts form rest)

v = a · t = 0.9 m/s² · 4.7 s = <u>4.2 m/s</u>

<u />

The distance traveled by the hare while accelerating can be calculated using the equation of the position:

x = x0 + v0 · t + 1/2 · a · t²      (x0 = 0 and v0 = 0)

x = 1/2 · a · t² = 1/2 · 0.9 m/s² · (4.7)² = <u>9.9 m</u>

<u />

Then, the hare runs at a constant speed of 4.2 m/s for 11.7 s. The distance traveled at constant speed will be:

x =  v · t

x = 4.2 m/s · 11.7 s = <u>49.1 m</u>

<u />

Then, the distance traveled by the hare while slowing down was:

Distance traveled while slowing down = 72 m - 49.1 m - 9.9 m = 13 m

Let´s find how much time it took the hare to come to stop, so we can calculate the acceleration. We know that when the position is 13 m, the velocity is 0.

v = v0 + a · t

0 = 4.2 m/s + a · t

-4.2 m/s / t = a

Replacing in the equation of the position:

x = v0 · t + 1/2 · a · t²      (considering x0 as the point at which the hare started to slow down)

13 m = 4.2 m/s · t - 1/2 · 4.2 m/s / t · t²

13 m = 4.2 m/s · t - 2.1 m/s · t

13 m = 2.1 m/s · t

t = 13 m / 2.1 m/s

t = 6.2 s

Then, the acceleration of the hare while slowing down will be:

-v0/t = a

-4.2 m/s / 6.2 s = a

a = -0.68 m/s²

The acceleration of the hare once it begins to slow down is -0.68 m/s²

The hare traveled 72 m in (6.2 s + 11.7 s + 4.7 s) 22.6 s. The tortoise reaches the final position of the hare at the same time, so, using the equation of the position we can calculate the acceleration of the tortoise:

x = x0 + v0 · t + 1/2 · a · t²     (x0 = 0 and v0 = 0)

x = 1/2 · a · t²

72 m = 1/2 · a · (22.6 s)²

144 m / (22.6 s)² = a

a = 0.28 m/s²

The acceleration of the tortoise is 0.28 m/s²

6 0
3 years ago
The latent heat of vaporization of a substance is the amount of energy associated with doing which of the following to 1 kg of t
mr Goodwill [35]
Converting it from liquid to gas
6 0
3 years ago
Read 2 more answers
5) Why does the first hill/drop on a roller coaster have to be the highest? (think about
prohojiy [21]

5) Due to the conservation of energy / due to the presence of friction

6) The work done is 4000 J

7) The distance travelled by the object is 4 m

8) The potential energy of the bird is 2450 J

Explanation:

5)

For a roller coaster in motion along the track, in absence of friction, the mechanical energy remains constant:

E=U+K = const.

where

U is the potential energy

K is the kinetic energy

At the beginning, the roller coaster is at rest, therefore its kinetic energy is zero and its mechanical energy is just equal to the potential energy:

E=U=mgh

where m is the mass of the roller coaster, g the acceleration of gravity, and h the height of the roller coaster above the ground at the first hill.

Since this amount of energy remains constant, the roller coaster cannot go to a higher hill: in fact, in that case it would reach a height h'>h, but this is not possible, because it would mean that its mechanical energy would be mgh' > E, larger than its mechanical energy, and since energy cannot be created (law of conservation of energy), the height of the next hills cannot be higher than the first one. Moreover, if we consider friction, then friction does work on the roller coaster in motion, and as a result, part of its mechanical energy is wasted (converted into thermal energy): therefore, the height of the following hills must be lower than the height of the first hill.

6)

The work done when lifting an object is equal to the gravitational potential energy gained by the object:

W=Fh

where

F is the weight of the object

h is the change in height of the object

For the object in this problem, we have

F = 200 N (weight)

h = 20 m (change in height)

Substituting, we find the work done:

W=(200)(20)=4000 J

7)

The work done when pushing an object in a direction parallel to the motion of the object is given by:

W=Fd

where

F is the magnitude of the force

d is the distance through which the object has travelled through

In this problem, we have:

W = 300 J (work done)

F = 75 N (magnitude of the force)

Solving the equation for d, we find the distance travelled:

d=\frac{W}{F}=\frac{300}{75}=4 m

8)

The potential energy of an object is the energy possessed by an object due to its position in a gravitational field. Near the Earth's surface, it is given by

PE=mgh

where

m is the mass of the object

g is the acceleration of gravity

h is the height of the object relative to the ground

For the bird in this problem, we have:

m = 5 kg (mass)

g=9.8 m/s^2

h = 50 m (height)

Substituting, we find:

PE=(5)(9.8)(50)=2450 J

Learn more about potential energy:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

6 0
3 years ago
Challenge Problem (Extra Credit) A car with bad shocks has a mass of 1500 kg. Before you go for a drive with three of your frien
Nastasia [14]

Answer:

167.354 m

Explanation:

We are given;

The mass of the car with bad shock;

m = 1500 kg

The distance at which the car sinks; x =

6 cm = 6 × 10^(−2) m

The total mass of 4 people; m_t = 11 kg

The total speed in the highway; V = 65

mph = 29.058 m/s

The spring's constant can be calculated from the formula;

F = Kx

F is also equal to mg.

Thus;

m_t × g = Kx

K = (m_t × g)/x

K = (11 × 9.81)/(6 × 10^(−2))

K = 1798.5 N/m

Mass of car and four people;m_(c+t) = 1500 + 11 = 1511 kg

Thus, the period cam be calculated from the formula;

T = 2π√((m_c+t)/k)

T = 2π√(1511/1798.5)

T = 5.759 s

the distance between adjacent bumps is calculated from;

Velocity = distance/time

Distance = velocity x time

Distance = 29.058 × 5.759

Distance = 167.354 m

4 0
4 years ago
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