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Rzqust [24]
4 years ago
15

How many grams of o2 are required to produce 7.00 g of co2?

Chemistry
1 answer:
Anna71 [15]4 years ago
7 0
Hey there!:

Molar mass:

O2 = 31.99 g/mol
CO2 = 44 g/mol

By the stoichiometry of the reaction:

C + O2 = CO2

31.99 g O2 --------------- 44 g CO2
mass O2 ------------------ 7.00 g CO2

mass O2 = ( 7.00 * 31.99 ) / 44

mass O2 = 223.93 / 44

mass O2 = 5.089 g
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Which of the following statements is true?
hammer [34]

Lord dragon you are wrong.

The answer is A: Incandescent light bulbs are almost 100 percent efficient. Because b-d do not make any sense.

8 0
3 years ago
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Determine the pH of a 5x10^-4 M solution of Ca(OH)2
miss Akunina [59]
Ca(OH)₂ ==> Ca²⁺ + 2 OH<span>-   

Ca(OH)</span>₂ is <span>strong Bases</span><span>

</span>Therefore,  the [OH-] equals 5 x 10⁻⁴ M. For every Ca(OH)₂ you produce 2 OH⁻<span>.
</span>
pOH = - log[ OH⁻]

pOH = - log [ <span>5 x 10⁻⁴ ]

pOH = 3.30

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5 0
3 years ago
While heating up a 25 gram sample of concrete (specific heat = 0.210-cal/g°C), your initial tempărature is room temperature (25°
Lana71 [14]

Answer:

Final temperature  = 83.1 °C

Explanation:

Given data:

Mass of concrete = 25 g

Specific heat capacity = 0.210 cal/g. °C

Initial temperature = 25°C

Calories gain = 305 cal

Final temperature = ?

Solution:

Q = m. c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

305 cal = 25 g ×0.210 cal/g.°C × T2 -  25°C

305 cal = 5.25cal/°C × T2 -  25°C

305 cal / 5.25cal/°C = T2 -  25°C

58.1 °C = T2 -  25°C

T2 = 58.1 °C + 25°C

T2 = 83.1 °C

7 0
3 years ago
Help would be majorly appreciated
Sophie [7]

Answer:

a) the atomic number is 15

b) the mass number is 15+16 = 31

c) element is phosphorus

d)Group 15 period 3

6 0
3 years ago
6.0 moles of Na and 4.0 moles of Cl2 are mixed, how manu moles of NaCl in moles cane be made from this mixture
Sladkaya [172]

Answer:

Moles of NaCl formed is 6.0 moles

Explanation:

We are given the equation;

2 Na(s) + Cl₂(g) → 2 NaCl(s)

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  • Moles of Cl₂ is 4.0 moles

From the reaction;

2 moles of sodium reacts with 1 mole of chlorine gas to form 2 moles of NaCl

In this case;

6 moles of Na would require 3 moles of Cl₂, this means that chlorine gas is in excess.

Thus, the rate limiting reagent is sodium.

But, 2 moles of sodium reacts to form 2 moles of NaCl

Therefore;

Moles of NaCl = Moles of Na

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Thus, moles of sodium chloride produced is 6.0 moles

3 0
3 years ago
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