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NISA [10]
3 years ago
15

How do you determine the acceleration of an object?

Physics
1 answer:
IgorC [24]3 years ago
8 0

Answer:

Divide the change in velocity by the time interval

Explanation:

Acceleration is defined as the rate of change of velocity.

mathematically it is the change in velocity divided by the time taken for that change.

i.e Divide the change in velocity by the time interval.

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Which of the following shows resistors in a parallel circuit
Alexeev081 [22]

The bottom drawing do

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3 years ago
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Nitrogen at 100 kPa and 25oC in a rigid vessel is heated until its pressure is 300 kPa. Calculate (a) the work done and (b) the
nignag [31]

Answer:

A. The work done during the process is W = 0

B. The value of heat transfer during the process Q = 442.83 \frac{KJ}{kg}

Explanation:

Given Data

Initial pressure P_{1} = 100 k pa

Initial temperature T_{1} = 25 degree Celsius = 298 Kelvin

Final pressure P_{2} = 300 k pa

Vessel is rigid so change in volume of the gas is zero. so that initial volume is equal to final volume.

⇒ V_{1} = V_{2} ------------- (1)

Since volume of the gas is constant so pressure of the gas is directly proportional to the temperature of the gas.

⇒ P ∝ T

⇒ \frac{P_{2} }{P_{1}} = \frac{T_{2} }{T_{1}}

⇒ Put all the values in the above formula we get the final temperature

⇒ T_{2} = \frac{300}{100} × 298

⇒ T_{2} = 894 Kelvin

(A). Work done during the process is given by W = P × (V_{2} -V _{1})

From equation (1), V_{1} = V_{2} so work done W = P × 0 = 0

⇒ W = 0

Therefore the work done during the process is zero.

Heat transfer during the process is given by the formula Q = m C_{v} ( T_{2} -T_{1} )

Where m = mass of the gas = 1 kg

C_{v} = specific heat at constant volume of nitrogen = 0.743 \frac{KJ}{kg k}

Thus the heat transfer Q = 1 × 0.743 × ( 894- 298 )

⇒ Q = 442.83 \frac{KJ}{kg}

Therefore the value of heat transfer during the process Q = 442.83 \frac{KJ}{kg}

6 0
3 years ago
At which point is cool air circulating beneath warm air?
stepan [7]

Answer:

1

Explanation:

5 0
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A 25 kg rock resting on the bottom of a lake must be moved from the paths of boats. The rock has a density of 2350 kg/m^3. What
algol13

Answer:

The force needed is the weight of the rock minus the buoyant force.

Explanation:

7 0
3 years ago
How much power will it take to move a 10 kg mass at an acceleration of 2 m/s² a distance of 10 meters in 5 seconds?
DedPeter [7]

Answer:

100 Watts

Explanation:

<u>These equations are needed to work out the answer:</u>

  • power= work done/ time taken
  • work done= force* distance
  • force= mass* acceleration

force: 10 kg* 2m/s= 20

work done: 20* 10m=200

power: 200/2=100

7 0
3 years ago
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