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yanalaym [24]
3 years ago
14

A bird flies at a speed of 4 m/s. It flies for 2160 seconds from its nest to the field. How much distance did the bird cover?

Physics
2 answers:
solniwko [45]3 years ago
8 0

Hello :D

For this applicate the formula:

\boxed{d=vt}

Data:

d = Distance = ?

v = Velocity = 4 m/s

t = Time = 2160 s

Replace according formula:

d = 4 m/s * 2160 s

  • Resolving:

d = 8640 m

Result:

The distance is of <u>8640 meters.</u>

Morgarella [4.7K]3 years ago
6 0

Answer:

The bird covers 8,640 m.

Explanation:

Distance= Speed×Time

Distance= 4×2160

Distance= 8,640

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The maximum speed of the object under simple harmonic motion is 0.786 m/s.

The given parameters:

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y = A sin(ωt + Ф)

where;

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The maximum speed of the object is calculated as follows;

V_{max} = A \omega\\\\V_{max} = 0.5 \times \frac{\pi}{2} = \frac{\pi}{4} \ m/s  = 0.786 \ m/s

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