Answer:
2.1 moles of water formed.
Explanation:
Given data:
Moles of water formed = ?
Moles of Ni(OH) = 4.20 mol
Solution:
Chemical equation:
2Ni(OH) → Ni₂O + H₂O
Now we will compare the moles of Ni(OH) with water.
Ni(OH) : H₂O
2 : 1
4.20 : 1/2×4.20 = 2.1 mol
2.1 moles of water formed.
Activation energy is the energy needed to start a reaction, eg the flame needed to start ... Collisions may have enough energy to react yet not react if the orientation of the molecules is incorrect. Difficult to explain here without graphics, but basically of the molecules are facing the wrong way it won't happen.
Dissolution means to make the compound apart, So when we have ionic compounds like NaI which has metal and non-metal ions, It separates into parts of positive ions and negative ions. After we separate this compound apart we will put the charge of each on above its symbol and then start to balance the equation of the dissolution.
So the dissolution equation of NaI is:
NaI(s) → Na^+(s) + I^-(Aqu)
Explanation:
When we move across a period from left to right then there will occur an increase in electronegativity and also there will occur an increase in non-metallic character of the elements.
As sulfur (S) is a group 16 element and chlorine (Cl) is a group 17 element. Hence, sulfur (S) is more metallic in nature than chlorine.
This means that chlorine (S) is less metallic than chlorine (Cl).
Both indium (I) and aluminium (Al) are group 13 elements. And, when we move down a group then there occur an increase in non-metallic character of the elements. As indium belongs to group 13 and period 5 whereas aluminium belongs to group 13 and period 3.
Therefore, aluminium (Al) is more metallic than indium (In).
Arsenic (Ar) is a group 15 element and bromine (Br) is a group 17 element. Therefore, arsenic is more metallic than bromine.
Replacement of methyl groups of camphor is a reduction mechanism. Camphor is a bridged bi-cyclic compound. If you observe the structure of camphor the methyl group is placed with one carbon bridge (7, 7) and two carbon bridge (1). Attack from face of one carbon bridge is termed as exo attack whereas from face of two carbon bridge is termed as endo attack. So replacement will lead to mix of both and formation of two stereo isomers.
Reduction mechanism is often shown with a U-shaped arrow pointing the attack by ion such as in nucleophilic addition reaction.
