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2 years ago

Express 10 as a product of prime factors in index form

Mathematics

1 answer:

telo118 [61]2 years ago

8 0

Answer:

product of prime factors: 2*5

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A bakery sells pastries in boxes of 7 each. If the bakery has 27 pastries, how many boxes can be filled?

skad [1K]

Answer:

3 with a few left over so 4

Step-by-step explanation:

4 0

2 years ago

12 stamps increased by 125% what is the new amount

GREYUIT [131]

12 x 1.25 = 15

15 is the new amount

4 0

2 years ago

If the polynomial

erik [133]

Answer:

Step-by-step explanation:

Given polynomial:

x¹⁹ + x¹⁷ + x¹³ + x⁷ + x⁵ + x³

Group as follows:

(x¹⁹ + x¹⁷) + (x¹³ + x¹¹) + (x⁷ + x⁵) + (x³ + x) - x =
x¹⁷(x² + 1) + x¹¹(x² + 1) + x¹⁵(x² + 1) + x(x² + 1) - x

As we see all terms have (x² + 1) as factor apart from the last one.

It means the remainder is - x

Correct choice is C

3 0

2 years ago

an auto store is having a sale on motor oil the chart shows the price per quarts as the numbers of quarts purchased increases us

Artyom0805 [142]

Answer:

Step-by-step explanation:

Use the attached given data to make a scatter plote. The diagram attached will aid you to do the plot.

please note you will have to merge each figure against each other.

Step 1

when number of quartz is = 1 , Price per quartz = 2. This will be merge against each other.

This step will be repeated for the remaining figure.

Conclusion

Since its a scatter plot we are not expecting a staright line graph.

7 0

3 years ago

A human resources representative claims that the proportion of employees earning more than $50,000 is less than 40%. To test thi

bearhunter [10]

Answer:

The statistic for this case would be:

$z=\frac{\hat p -p_o}{\sqrt{\frac{\hat p(1-\hat p)}{n}}}$

And replacing we got:

$z= \frac{0.436-0.4}{\sqrt{\frac{0.436*(1-0.436)}{700}}}= 1.92$

Step-by-step explanation:

For this case we have the following info:

$n =700$ represent the sample size

$X= 305$ represent the number of employees that earn more than 50000

$\hat p=\frac{305}{700}= 0.436$

We want to test the following hypothesis:

Nul hyp. $p \leq 0.4$

Alternative hyp : $p>0.4$

The statistic for this case would be:

$z=\frac{\hat p -p_o}{\sqrt{\frac{\hat p(1-\hat p)}{n}}}$

And replacing we got:

$z= \frac{0.436-0.4}{\sqrt{\frac{0.436*(1-0.436)}{700}}}= 1.92$

And the p value would be given by:

$p_v = P(z>1.922)= 0.0274$

4 0

3 years ago