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sveticcg [70]
3 years ago
14

A quarterback back pedals 3.3 meters southward and then runs 5.7 meters northward. For this motion, what is the distance moved?

What is the magnitude and direction of the displacement?
Physics
1 answer:
mixas84 [53]3 years ago
8 0

Answer:

The distance moved is 9 meters

The magnitude of the displacement is 2.4 meters

The direction of the displacement is northward

Explanation:

- <em><u>Distance</u></em> is the length of the actual path between the initial and the

  final position. Distance is a scalar quantity

- <u><em>Displacement</em></u> is the change in position, measuring from its starting

  position to the final position. Displacement is a vector quantity

The quarterback pedals 3.3 meters southward

That means it moves down 3.3 meters

Then runs 5.7 meters northward

That means it runs up 5.7 meters

The distance = 3.3 + 5.7 = 9 meters

<em></em>

<em>The distance moved is 9 meters</em>

It moves southward (down) for 3.3 meters and then moves northward

(up) for 5.7

It moves from zero to 3.3 down and then moves up to 5.7

The displacement = 5.7 - 3.3 = 2.4 meters northward

<em />

<em>The magnitude of the displacement is 2.4 meters</em>

<em>The direction of the displacement is northward</em>

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