Answer:
a) T = 1,467 s
, b) A = 0.495 m
, c) v = 4.97 10⁻² m / s
Explanation:
The simple harmonic movement is described by the expression
x = A cos (wt + Ф)
Where the angular velocity is
w = √ k / m
a) Ask the period
Angular velocity, frequency and period are related
w = 2π f = 2π / T
T = 2π / w
T = 2pi √ m / k
T = 2π √ (1.2 / 22)
T = 1,467 s
f = 1 / T
f = 0.68 Hz
b) ask the amplitude
The mechanical energy of a harmonic oscillator
E = ½ k A²
A = √2 E / k
A = √ (2 2.7 / 22)
A = 0.495 m
c) the mass changes to 8.0 kg
As released from rest Ф = 0, the equation remains
x = A cos wt
w = √ (22/8)
w = 1,658
x = 3.0 cos (1,658 t)
Speed is
v = dx / dt
v = -A w sin wt
The speed is maximum when without wt = ±1
v = Aw
v = 0.03 1,658
v = 4.97 10⁻² m / s
Explanation:
The given data is as follows.
C =
R =
ohm
C
Q =
Formula to calculate the time is as follows.
0.135 =
= 7.407
t = 4.00 s
Therefore, we can conclude that time after the resistor is connected will the capacitor is 4.0 sec.
Answer :
(a). The speed of the block is 0.395 m/s.
(b). No
Explanation :
Given that,
Diameter = 20.0 cm
Power = 26.0 MW
Mass = 110 kg
diameter = 20.0 cm
Distance = 100 m
We need to calculate the pressure due to laser
Using formula of pressure
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![P_{r}=\dfrac{P}{Ac}Put the value into the formula[tex]P_{r}=\dfrac{26.0\times10^{6}}{\pi\times(10\times10^{-2})^2\times3\times10^{8}}](https://tex.z-dn.net/?f=P_%7Br%7D%3D%5Cdfrac%7BP%7D%7BAc%7D%3C%2Fp%3E%3Cp%3EPut%20the%20value%20into%20the%20formula%3C%2Fp%3E%3Cp%3E%5Btex%5DP_%7Br%7D%3D%5Cdfrac%7B26.0%5Ctimes10%5E%7B6%7D%7D%7B%5Cpi%5Ctimes%2810%5Ctimes10%5E%7B-2%7D%29%5E2%5Ctimes3%5Ctimes10%5E%7B8%7D%7D)

We need to calculate the force
Using formula of force
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
Put the value into the formula


We need to calculate the acceleration
Using formula of force

Put the value into the formula



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(a). We need to calculate speed of the block
Using equation of motion
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Put the value into the formula
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
(b). No because the velocity is very less.
Hence, (a). The speed of the block is 0.395 m/s.
(b). No