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3 years ago

When the area over which pressure is applied is increased,

Physics

1 answer:

Tema [17]3 years ago

3 0

Answer:

A. the pressure decrease

Explanation:

pressure decreases when the surface area over which a force is applied increases. pressure increases when the surface area over which force is applied decreases.

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Two particles have a mass of 8kg and 12kg, respectively. if they are 800mm apart, determine the force of gravity acting between

natima [27]

The magnitude of the force of gravity acting between the particles is:
$F=G\frac{m_1.m_2}{d^2}$
The weight of each particle is:
$P=mg$
Now let's plug in the numbers knowing that $G=6.67\times10^{-11}$ , $g=9.81$ , $d=0.8$ and m1 and m2 are already given in kilograms. We get then:
$P_1=m_1.g=78.48$ N
$P_2=m_2.g=117.72$ N
$F=G\frac{m_1.m_2}{d^2}=1.00\times10^{-8}$ N

This results shows us why we don't often see objects being attracted to each other, their mass is too small compared to the earth gravitational pull.

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3 years ago

A jaguar starts from rest and reaches its maximum speed in 5 seconds. If its acceleration is 5.0 m/s/s, what is its maximum spee

trasher [3.6K]

Answer:10

Explanation:because 5x10=50 and if you take away the decimal it is wrote "50"

3 0

3 years ago

The ability of matter to easily combine chemically with other substances is know as?

skelet666 [1.2K]

Reactivity is the ability of matter that allows it to easily chemically combine with other substances.

4 0

3 years ago

Read 2 more answers

In 1996, astronomers discovered an icy object beyond pluto that was given the designation 1996 tl 66. it has a semimajor axis of

antoniya [11.8K]

Answer : 2446 years.

Explanation :

Length of semi major axis is, $a=84\ au= 1.496\times 10^{11}\ m$

According to Kepler's third law, square of time period of an orbit is directly proportional to the cube of the semi major axis.

i.e $T^2=\dfrac{4\pi^2}{GM}a^3$

where G is gravitational constant

M is mass of sun, $M=1.98\times 10^{30}\ Kg$

So, $T^2=\dfrac{4\times (3.14)^2}{6.6\times 10^{-11}Nm^2/Kg\times 1.98\times 10^{30}\Kg}$

$T^2=3\times 10^{-19}\times(84\times 1.496\times 10^{11})^3$

$T^2=3\times 10^{-19}\times 1984415.6\times 10^{33}$

$T^2=59532469.8\times 10^{14}\ s$

$T=7715.7\times 10^7\ s$

since, $1\ sec=3.17\times 10^{-8}\ years$

So, orbital period is approximately 2446 years.

7 0

4 years ago

A 45.00 kg person in a 43.00 kg cart is coasting with a speed of 19 m/s before it goes up a hill. there is no friction, what is

HACTEHA [7]

Answer:

the maximum vertical height the person in the cart can reach is 18.42 m

Explanation:

Given;

mass of the person in cart, m₁ = 45 kg

mass of the cart, m₂ = 43 kg

acceleration due to gravity, g = 9.8 m/s²

final speed of the cart before it goes up the hill, v = 19 m/s

Apply the principle of conservation of energy;

$mgh_{max} = \frac{1}{2}mv^2_{max}\\\\ gh_{max} = \frac{1}{2}v^2_{max}\\\\h_{max} = \frac{v^2_{max}}{2g} \\\\h_{max} =\frac{(19)^2}{2\times 9.8} \\\\h_{max} = 18.42 \ m$

Therefore, the maximum vertical height the person in the cart can reach is 18.42 m

5 0

3 years ago