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3 years ago

Is the equation below an example of growth or decay y=4x

2 answers:

8 0

Its representing growth if im comprehending what you're asking because it has a slope of a positive 4.... would like brainliest if correct plzzz

ElenaW [278]3 years ago

3 0

It is growth because it is a positive equation.

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Triangle GCH is similar to triangle DCE. Find CH

soldier1979 [14.2K]

Answer:

x = 65

Step-by-step explanation:

if two triangles are similar then we can use the similarity ratio to find the length of CH

60/156 = x/169 cross multiply expressions

156x = 10140 divide both sides by 156

x = 65

5 0

3 years ago

A bike lock has a 3 digit combination. Each character can be any digit from 3-8. The only restriction is that all 3 characters c

lesya [120]

Answer:

The number of possible combinations is 180

Step-by-step explanation:

The numbers to select from are 3-8

These are 6 numbers

Now, the restriction we have is that the 3 characters cannot be the same

For the first character, we have 6 choices;

For the second character, we have another 6 choices

For the last character, since it cannot be the same, we can only have 5 choices

So the possible number of choices will be;

6 * 6 * 5 = 189 combinations

7 0

3 years ago

A ball of radius 15 has a round hole of radius 5 drilled through its center. Find the volume of the resulting solid. Hint: The u

OverLord2011 [107]

Answer:

The volume of the ball with the drilled hole is:

$\displaystyle\frac{8000\pi\sqrt{2}}{3}$

Step-by-step explanation:

See attached a sketch of the region that is revolved about the y-axis to produce the upper half of the ball. Notice the function y is the equation of a circle centered at the origin with radius 15:

$x^2+y^2=15^2\to y=\sqrt{225-x^2}$

Then we set the integral for the volume by using shell method:

$\displaystyle\int_5^{15}2\pi x\sqrt{225-x^2}dx$

That can be solved by substitution:

$u=225-x^2\to du=-2xdx$

The limits of integration also change:

For x=5: $u=225-5^2=200$

For x=15: $u=225-15^2=0$

So the integral becomes:

$\displaystyle -\int_{200}^{0}\pi \sqrt{u}du$

If we flip the limits we also get rid of the minus in front, and writing the root as an exponent we get:

$\displaystyle \int_{0}^{200}\pi u^{1/2}du$

Then applying the basic rule we get:

$\displaystyle\frac{2\pi}{3}u^{3/2}\Bigg|_0^{200}=\frac{2\pi(200\sqrt{200})}{3}=\frac{400\pi(10)\sqrt{2}}{3}=\frac{4000\pi\sqrt{2}}{3}$

Since that is just half of the solid, we multiply by 2 to get the complete volume:

$\displaystyle\frac{2\cdot4000\pi\sqrt{2}}{3}$

$=\displaystyle\frac{8000\pi\sqrt{2}}{3}$

5 0

3 years ago

An editor has a stack of k documents to review. The order in which the documents are reviewed is random with each ordering being

ladessa [460]

Using the probability concept, it is found that there is a $\mathbf{\frac{1}{k}}$ probability that “Relaxation Through Mathematics” is first to review.