Answer:
The work done on the athlete is approximately 2.09 J
Explanation:
From the definition of the work done by a variable force:
and substituting with the function of our problem:
.
1 answer:
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First overtone of open organ pipe is given as
first overtone of closed organ pipe is given as
now they are in unison so we will have
so end correction of both pipes is e = 1 cm