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Dominik [7]
3 years ago
11

QUESTION 17

Chemistry
1 answer:
borishaifa [10]3 years ago
5 0

Question 17:

False; cutting hair would change what it looks like but, braiding it keeps it the same substance it is.


Question 18 :

My best guess would either be A or D. I would lean more towards D because if there are different mixtures then it depends on what you are mixing.


Hope it helps in some way. <3

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Write the ka expression for an aqueous solution of hypochlorous acid:
sveticcg [70]
Balanced chemical reaction (dissociation) of <span>an aqueous solution of hypochlorous acid:
HClO(aq) </span>⇄ H⁺(aq) + ClO⁻(aq).
Ka = [H⁺] · [ClO⁻] / [HClO].
[H⁺] is equilibrium concentration of hydrogen cations or protons.
[ClO⁻] is equilibrium concentration of <span>hypochlorite anions.
</span>[HClO] is equilibrium concentration <span> of hypochlorous acid.
</span>Ka is t<span>he acid dissociation constant.</span>
7 0
3 years ago
Choose the solvent below that would show the greatest boiling point elevation when used to make a 0.10 m nonelectrolyte solution
postnew [5]

Answer is: 1) ccl4, kb = 29.9°c/m, carbon tetrachloride has the greatest boiling point elevation.

The boiling point elevation is directly proportional to the molality of the solution according to the equation: ΔTb = Kb · b.

<span> ΔTb -  the boiling point elevation.
Kb - the ebullioscopic constant.
b - molality of the solution.
So the highest boiling poing elevation will be for solution with highest ebullioscopic constant because molality is the same.</span>

5 0
3 years ago
Read 2 more answers
What is the difference expressed in kilograms between the mass of proton and the mass of electon?
Mashutka [201]
Particle, Relative Mass<span>, Actual </span>Mass<span> (g) </span>Electron<span>- 1 , 9.11*10 power -28 g. ... Calculate: What is the diff </span>expressed in kg between the mass<span> of a </span>proton and the mass<span> ... Best Answer: </span>difference<span>in </span>mass<span> = [1.673 x 10^(-24) - 9.11 x ...</span>
4 0
4 years ago
Read 2 more answers
If 15.0 liters of neon at 25.0 °C is allowed to expand to 45.0 liters, what must the new temperature be to maintain constant pre
Fed [463]

Answer:

893K=620 °C

Explanation:

PV=nRT

P=nRT/V

P= (1 mol* 0.0821* 298K)/15L      P=1.63 atm

T=PV/nR

T=(1.63 atm*45 L)/(1 mol*0.0821)

T= 893K=620 °C

7 0
3 years ago
Place each noble gas symbol in front of the appropriate partial electron configuration to create an accurate electron configurat
nydimaria [60]

The noble gas that precedes a given partial electron configuration must <em>itself </em>have an electron configuration that is complete <em>up to </em>the partial electron configuration. The noble gas's electron configuration should, when fully written out right before the partial electron configuration, give us a valid electron configuration for some element.

For the first series, the highest principal energy level has the number 4, so our noble gas should <em>at least </em>be one that is in the third period (numerically, the energy level is the same as the period number). That noble gas would be argon. The partial electron configuration given is not that of a noble gas (note: all noble gases have an electron configuration that contains <em>N</em>p⁶, where <em>N </em>= the highest principal energy level). So, the noble gas that appropriately precedes our first partial electron configuration is [Ar].

Argon's electron configuration is 1s²2s²2p⁶3s²3p⁶. Using the Aufbau Principle, 4s² would correctly follow 3p⁶. [Ar]4s²3d¹⁰4p² is equivalent to writing out 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p²; either way, this would happen to be the electron configuration of germanium.

Now that we hopefully have our fundamentals down, we can apply them to figure out the noble gases that precede the remaining partial electron configurations.

[Kr]5s²4d¹⁰5p⁵: This is the electron configuration of iodine.

[He]2s²2p⁵: This is the electron configuration of fluorine.

[Xe]6s²4f¹⁴5d¹⁰6p²: This is the electron configuration of lead.

[Ne]3s²2: This is the electron configuration of magnesium.

5 0
3 years ago
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