Answer:
79.91% of loaves are between 26.94 and 32.18 centimeters
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
What percentage of loaves are between 26.94 and 32.18 centimeters
This is the pvalue of Z when X = 32.18 subtracted by the pvalue of Z when X = 26.94.
X = 32.18:
has a pvalue of 0.8621
X = 26.94:
has a pvalue of 0.0630
0.8621 - 0.0630 = 0.7991
79.91% of loaves are between 26.94 and 32.18 centimeters
Hello there. Sorry from last time.
What is the standard deviation of the possible outcomes? Roundyour answer to two decimal places.
<span>B.12.55</span>
The set of rational plus irrational numbers equals ALL REAL NUMBERS
Yes, it is a function because every x-value maps into only one y-value. In other words, because rational and irrational are mutually exclusive, x does not map into both 0 and 1
Domain is all real numbers.
Range is 0 or 1
y-intercept happens when x=0, so that is a rational number and y = 1
There are an infinite number of x-intercepts. Every irrational number is an x-intercept
Neither even or odd because it is not symmetric with either the y-axis or the origin.
The graph jumps between y=0 and y=1
Hope that helps Answer:
Step-by-step explanation:
Answer:
\frac{1}{2} \left[\begin{array}{ccc}16&6&2\\20&8&2\\7&3&1\end{array}\right]
Step-by-step explanation:
Given is a matrix 3x3 as
![\left[\begin{array}{ccc}1&0&2\\-3&1&4\\2&-3&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%262%5C%5C-3%261%264%5C%5C2%26-3%264%5Cend%7Barray%7D%5Cright%5D)
|A| =2 hence inverse exists.
Cofactors are 16 20 7
6 8 3
2 2 1
Hence inverse =
![\frac{1}{2} \left[\begin{array}{ccc}16&6&2\\20&8&2\\7&3&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D16%266%262%5C%5C20%268%262%5C%5C7%263%261%5Cend%7Barray%7D%5Cright%5D)
Answer: yes lol
Step-by-step explanation:
