In the given diagram, the value of the dashed side of rhombus OABC is 5
<h3>Distance between two points </h3>
From the question, we are to determine the length of the dashed line (OA), in rhombus OABC
In the diagram, we can observe that the length of OA is the distance between point A and the origin (O).
Using the formula for calculating distance between two points,
d =√[(x₂-x₁)² + (y₂-y₁)²]
In the diagram,
The coordinate of the origin is (0, 0)
The coordinate of point A is (3, 4)
Thus,
x₁ = 0
x₂ = 3
y₁ = 0
y₂ = 4
Putting the parameters into the formula, we get
OA =√[(3-0)² + (4-0)²]
OA =√(3² + 4²)
OA =√(9+16)
∴ OA =√25
OA = 5
Hence, in the given diagram, the value of the dashed side of rhombus OABC is 5
Learn more on Distance between two points here: brainly.com/question/24778489
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Plz explain clearly so i can answer
Your answer should be the third and forth options
It would be 89.
You can also just look up a list of prime numbers online.
Answer:
a) 34
b) 30
Step-by-step explanation:
so the nth term is just the position on the term, so if u want to find the 5th term you just have to substitute 5 in for n and solve!
a) 6n + 4
= 6(5) + 4
= 30 + 4
= 34 --> the 5th term for a sequence defined by 6n+4 is 34
b) n^2 + 5
= (5)^2 + 5
= 25 + 5
= 30 --> the 5th term for a sequence defined by n^2 + 5 is 30
hope this helps!
