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Helen [10]
3 years ago
6

Denise conducts a study to find out which of three subway routes gets her to work in the shortest amount of time. in denise's ex

periment, the independent variable is the __________ , and the dependent variable is the __________ .
Business
2 answers:
Varvara68 [4.7K]3 years ago
8 0
The independent variable is the subway routes it is because an independent variable is a type of variable that can stand alone without being changed by other variables.
The dependent variable is the shortest amount of time, it is because the result is dependent the factors such as the subway routes, if whether which of three can get her to work in the shortest amount of time.
kotykmax [81]3 years ago
4 0

Answer:

Independent variable : Subway routes

Dependent variable : Time

Explanation:

Dependent variable are outputs that are derived from an altered input . In other words the outcome depends on adjustment to a set of independent variable. In research and experiments , the variable output is always being tested to see how it will react to independent variable

Independent variable are the sets of variable that are manipulated in an experiment in order to know its effect on the variables that rely on it .Any changes to the independent variable will definitely affect the variables that depend on it .

In the question , we can see that the amount of time is dependent on the subway routes followed to work. Any changes to the route will affect the time in either ways.

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For customers purchasing a refrigerator at a certain appliancestore, let A be the event that the refrigerator wasmanufactured in
V125BC [204]

Answer:

Part a : The tree diagram is attached with the solution.

Part b: The probability of P(A∩B∩C) is 0.5519.

Part c: The probability of P(B∩C) is 0.6976.

Part d: The probability of P(C) is 0.7658.​

Part e: The probability of P(A∣B∩C) is 0.7658.​

Explanation:

The solution is as follows.

Data Given is as

P(A) = 0.73

P(B | A) = 0.90

P(B | A' ) =0.76

P(C | A∩B) =0.84

P(C | A∩B' ) =0.65

P(C | A' ∩B) =0.71

P(C | A' ∩B' ) =0.32

Part a:

The remaining values of Probabilities for the tree formation are calculated as follows

P(A')=1-P(A)=1-0.73=0.27

P(B'|A)=1-P(B|A)=1-0.90=0.10

P(B' | A' )=1-P(B | A' ) =1-0.76=0.24

P(C' | A∩B) =1-P(C | A∩B)=1-0.84=0.16

P(C' | A∩B' ) =1-P(C | A∩B' ) =1-0.65=0.35

P(C' | A' ∩B) =1-P(C | A' ∩B) =1-0.71=0.29

P(C' | A' ∩B' ) =1-P(C | A' ∩B' )=1-0.32=0.68

so the probability tree is given as attached in the diagram.

Part b:

P(A∩B∩C)=P(A)P(B∣A)P(C∣A∩B)

From the above data in part a

P(A)=0.73, P(B|A)=0.90 and P(C∣A∩B)=0.84

                =0.73×0.90×0.84

               =0.55188

               ≈0.5519

The probability of P(A∩B∩C) is 0.5519.

Part c

P(B∩C)=P(A∩B∩C)+P(A'∩B∩C)

           = [P(A)P(B∣A)P(C∣A∩B)+{1−P(A)}P(B∣A′)P(C∣A′∩B)]

From the above data

P(A)=0.73,P(B∣A)=0.9,P(C∣A∩B)=0.84,P(B∣A′)=0.76 and P(C∣A′∩B)=0.71

P(B∩C)= [P(A)P(B∣A)P(C∣A∩B)+{1−P(A)}P(B∣A′)P(C∣A′∩B)]

           =(0.73×0.9×0.84)+(1−0.73)×0.76×0.71

           =0.55188+0.145692

           =0.697572

           ≈0.6976

The probability of P(B∩C) is 0.6976.

Part d

P(C)=P(A∩B∩C)+P(A′∩B∩C)+P(A∩B ′∩C)+P(A′∩B ′∩C)

      =P(A)P(B∣A)P(C∣A∩B)+[1−P(A)]P(B∣A′)P(C∣A′∩B)+P(A)[1−P(B∣A)]P(C∣A∩B′)+            

        [1−P(A)][1−P(B∣A′)]P(C∣A′∩B′)

Here from above data

P(A)=0.73,P(B∣A)=0.9,P(C∣A∩B)=0.84,P(B∣A′)=0.76,P(C∣A∩B′)=0.65,P(C∣A′∩B′)=0.32 and P(C∣A′∩B)=0.71

P(C)=P(A)P(B∣A)P(C∣A∩B)+[1−P(A)]P(B∣A′)P(C∣A′∩B)+P(A)[1−P(B∣A)]P(C∣A∩B′)+            

        [1−P(A)][1−P(B∣A′)]P(C∣A′∩B′)

     ={0.7x0.9x0.84}+{(1-0.73)x0.76×0.71}+{0.73x(1-0.9)x0.32}+{(1-0.73)x(1-          

       0.76)x0.32}

     =0.55188+0.145692+0.04745+0.020736

     =0.765758

     ≈0.7658

The probability of P(C) is 0.7658.​

Part e

From part (b),P(A∩B∩C)=0.55188

From part (c), P(B∩C)=0.697572

<em>By  conditional probability rule, </em>

P(A∣B∩C)= P(A∩B∩C)/P(B∩C)

​        = 0.55188/0.697572

              =0.791144

             ≈0.7911

The probability of P(A∣B∩C) is 0.7658.​

​

​

​

6 0
3 years ago
Logistics means creating an efficient assembly line.<br> A. <br> True<br> B. <br> False
Vlad [161]

Answer:

False

Explanation:

The answer is false.

6 0
3 years ago
Read 2 more answers
manufacturing costs for August when production was 1,000 units appear below: Direct material $12 per unit Direct labor $7,500 Va
avanturin [10]

Answer:

Total manufacturing Cost $42,250

Explanation:

The computation of the flexible budget manufacturing cost amount for a month when 900 units are produced is given below:

No. of units Produced 900 units

Direct material at $12 per unit $10,800

Direct labor (($7,500 ÷1,000) × 900) $6,750

Variable Overhead ($6,000 ÷ 1000) × 900    $5,400

Factory depreciation $9,000

Factory Supervisory salary  $7,800

other fixed factory cost $2,500

Total manufacturing Cost $42,250

7 0
3 years ago
Your recently widowed grandma says, “i feel granddaddy's presence all the time. he's actually guiding me to do the right thing.”
Tema [17]
The reason that the grand ma is recently widowed will make it likely that the person should treat her in a way that her feelings won't get hurt. The likely response for the given scenario above is to tell her that grand pa is probably doing that, in order for her to be happy and not to deny in a way that she is experiencing it because she longs for him and misses him.
6 0
3 years ago
Early in January, the following transactions were carried out by Maxwell Communications. Sold capital stock to owners for $35,00
Rina8888 [55]

Answer:

Part a

                                Assets                     Liabilities               Owners Equity

Balances              $308,250                   $108,250                   $200,000

Part b

Transaction #         Assets                     Liabilities                  Owners Equity

1                       + $35,000 (Cash)                nill                    + $35,000 (Capital)

2                      + $35,000 (Land)        +67,500 (Note Payable)          nill

                       + $55,000(Buildings)

                       - $22,500 (Cash)

3                      + $9,500 (Office Equi)  + $9,500 (Acco Payable)      nill

4                      +$20,000 (Cash)          +$20,000(Note Payable)       nill

5                     - $22,250 (Cash)           -$20,000(Acco Payable)       nill

Explanation:

<em>Hi, I have attached the full question below as images.</em>

Part a

Here simply calculated the totals of Assets, Liabilities and Owners Equity at December 31.

Part b

Remember for every transaction, there are two or more accounts affected. To find the effect of transactions, the first step is to identify the the Accounts affected and the amounts to effect these accounts. Determine if the Account is being increased or decreased. Lastly record the effect as required under the Element of Assets, Liabilities and Equity.

4 0
3 years ago
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