is the Calcium
because the calcium in group two which group two has 2 electron and also calcium and Potassium 4s sub level group potassium has 1 electron. :)
Answer:
The total mass of D-Glucose dissolved in a 2μL aliquot is 1 E-4 g
Explanation:
providing a solution to 5% weight-volume as found in commerce:
⇒ % 5 = (5g d-glucose/ 100 mL sln)×100
⇒ 0.05 = g C6H12O6/mL sln
⇒ g C6H12O6 = (2 μL sln)×(0.001 mL/μL)×(0.05 g C6H12O6/mL sln)
⇒ g C6H12O6 = 1 E-4 g C6H12O6
Answer:- C. 16.4 L
Solution:- The given balanced equation is:
From this equation, there is 2:1 mol ratio between HCl and hydrogen gas. First of all we calculate the moles of hydrogen gas from given grams of HCl using stoichiometry and then the volume of hydrogen gas could be calculated using ideal gas law equation, PV = nRT.
Molar mass of HCl = 1.008 + 35.45 = 36.458 gram per mol
The calculations are shown below:
= 
Now we will use ideal gas equation to calculate the volume.
n = 0.672 mol
T = 25 + 273 = 298 K
P = 101.3 kPa = 1 atm
R = 
PV = nRT
1(V) = (0.672)(0.0821)(298)
V = 16.4 L
From calculations, 16.4 L of hydrogen gas are formed and so the correct choice is C.
Answer:
The solution is not ideal and shows a positive deviation from Raoult’s law since Psolution (experimental) > Psolution (actual).
Explanation:
Number of moles of CS2 = 3.95g/76.13gmol-1 = 0.0519 moles
Number of moles of acetone = 2.43g/58.08gmol-1 = 0.0418 moles
Total number of moles = 0.0937 moles
Mole fraction of CS2 = 0.0519/0.0937 = 0.5538
Mole fraction of acetone = 0.0418/0.0937 = 0.4461
From Raoult’s law;
PCS2 = 0.5538 × 515 torr = 285.207 torr
Pacetone = 0.4461 × 332 torr = 148.1052 torr
Total pressure = 285.207 torr + 148.1052 torr = 433.3 torr
