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Goshia [24]
4 years ago
9

The reaction 2 no(g) + cl2(g) → 2 nocl(g) is carried out in a closed vessel. if the partial pressure of no is decreasing at a ra

te of 184 torr/min, what is the rate of change of the total pressure in the vessel? the sign of the answer is important.
Chemistry
1 answer:
BARSIC [14]4 years ago
4 0

Answer:

92.0 torr/min.

Explanation:

  • For the reaction: <em>2NO(g) + Cl₂(g) → 2NOCl(g).</em>

∵ The rate of the reaction = - 1/2(ΔP)NO/Δt = - (ΔP)Cl₂/Δt = 1/2(ΔP)NOCl/Δt.

∵ (ΔP)NO/Δt = - 184 torr/min.

<em>∴ The rate of change of the total pressure in the vessel = - 1/2(ΔP)NO/Δt</em> = (- 1/2)(- 184 torr/min) = <em>92.0 torr/min.</em>

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Answer:

0.1935atm is the pressure of the gas.

Explanation:

In the problem you have the mass of Neon (You can obtain moles using molar mass), you have volume, and temperature. You can use general ideal gas law to solve pressure:

PV = nRT

P = nRT / V

<em>Where P is pressure in atm, n are moles, R is gas constant (0.082atmL/molK), T is absolute temperature (20.0°C + 273.15 = 293.15K), and V is volume in L = Volume in dm³</em>

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<em>Moles gas:</em>

Molar mass Ne = 20.1797g/mol

0.325g * (1mol / 20.1797g) = 0.0161 moles

Replacing:

P = nRT / V

P = 0.0161 moles * 0.082atmL/molK * 293.15K / 2L

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The density of an unknown gas at 98°C and 740 mmHg is 2.50 g/L. What is the molar mass of the gas with work showed?
noname [10]

Answer:

78.2 g/mol  

Step-by-step explanation:

We can use the <em>Ideal Gas Law</em> to solve this problem:

       pV = nRT

Since n = m/M, the equation becomes

      pV = (m/M)RT     Multiply each side by M

   pVM = mRT               Divide each side by pV

        M = (mRT)/(pV)

Data:

ρ = 2.50 g/L

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T =98 °C

p = 740 mmHg

Calculation:

(a)<em> Convert temperature to kelvins </em>

T = (98 + 273.15) = 371.15 K

(b) <em>Convert pressure to atmospheres </em>

p = 740 × 1/760 =0.9737 atm

(c) <em>Calculate the molar mass </em>

Assume V = 1 L.

   Then m = 2.50 g

            M = (2.50 × 0.082 06 × 371.15)/(0.9737 × 1)

                = 76.14/0.9737

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The type of nuclear decay in which Oxygen decays to form nitrogen is beta plus decay.

<h3>What is a beta plus decay?</h3>

A beta plus decay is a type of decay in which a proton in an element disintegrates to produce a neutron resulting in a decrease in the atomic number of the radioactive element.

In the given equation below:

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Oxygen decays to form nitrogen due to a decrease in atomic number.

This is an example of beta plus decay.

In conclusion, oxygen decays to form nitrogen beta plus decay.

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