Answer:
a rock of 50kg should be placed =drock=0.5m from the pivot point of see saw
Explanation:
τchild=τrock
Use the equation for torque in this equation.
(F)child(d)child)=(F)rock(d)rock)
The force of each object will be equal to the force of gravity.
(m)childg(d)child)=(m)rockg(d)rock)
Gravity can be canceled from each side of the equation. for simplicity.
(m)child(d)child)=(m)rock(d)rock)
Now we can use the mass of the rock and the mass of the child. The total length of the seesaw is two meters, and the child sits at one end. The child's distance from the center of the seesaw will be one meter.
(25kg)(1m)=(50kg)drock
Solve for the distance between the rock and the center of the seesaw.
drock=25kg⋅m50kg
drock=0.5m
Answer:
v = √k/m x
Explanation:
We can solve this exercise using the energy conservation relationships
starting point. Fully compressed spring
Em₀ =
= ½ k x²
final point. Cart after leaving the spring
= K = ½ m v²
Em₀ = Em_{f}
½ k x² = ½ m v²
v = √k/m x
Answer:
750J
Explanation:
Given parameters:
Mass of the object = 0.15kg
Velocity of the object = 100m/s
Unknown:
Kinetic energy of the body = ?
Solution:
The kinetic energy is the energy due to the motion of a body. It is mathematically expressed as;
K.E =
m v²
m is the mass of the body
v is the velocity
Now insert the parameters and solve;
K.E =
x 0.15 x 100² = 750J
Answer:
the acceleration of a moving object
Explanation: