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Lostsunrise [7]
3 years ago
8

Can Someone Please help

Physics
1 answer:
ololo11 [35]3 years ago
8 0

Answer:

Yes ,the balloon gets stick to Wood,wall etc

Explanation:

Because of static friction between two surfaces

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a fly wheel of mass 12kg and radius 0.5m with wrapped around it.on the end of the rope is 2kg load.intially it is at rest.calcul
leva [86]

Answer:

19.6 N of torque. The 2kg load is being affected by acceleration due to gravity which is 9.8 m/s^s

Explanation:

2×9.8=19.6

6 0
2 years ago
Greg is giving a slide show presentation to a large audience. How might a laser best help him with the presentation?
gizmo_the_mogwai [7]

Explanation :

The full form of laser is Light Amplification by Stimulated Emission of Radiation. It has particles of very high energy. It points in one direction.

Greg is giving a slide show presentation to a large audience. It is very important to make the presentation informative. By using a laser, we can focus on the important part of the presentation. So that we can highlight the important points.

3 0
3 years ago
Read 2 more answers
Calculate the force between charges of 5.0 x 10^-8 c and 1.0 x 10^-7 if they are 5.0 feet apart
weqwewe [10]

Answer:

F = 19.375 x 10^-6  N

Explanation:

This problem can be solved by applying Coulomb's Law, which lets us determine the force between two electrically charged particles.

It is defined as

F = (ke * q1 * q2)/ r^2

Where,

ke =  is Coulomb's constant ≈ 9×10^9 N⋅m^2⋅C^−2

q1 = 5.0 x 10^-8 C

q2 = 1.0 x 10^-7 C

r = 5 ft = 1,524 m

F  = (9×10^9 N⋅m^2⋅C^−2)*(5.0 x 10^-8 C)*(1.0 x 10^-7 C)/ ((1,524 m)^2)

F  = (9×10^9 N⋅m^2⋅C^−2)*(5.0 x 10^-8 C)*(1.0 x 10^-7 C)/ ((1,524 m)^2)

F = 19.375 x 10^-6  N

6 0
3 years ago
if S = at² + bt + c, where S is the distance, and t is the time, find the correct unit of a, b and c​
oksian1 [2.3K]

Answer:

a is in units of \frac{m}{s^{2}}

b is in units of \frac{m}{s}

c is in units of m

Explanation:

We have the following expression:

S=at^{2}+bt+c

Where:

S is the distance, hence its unit is m (meters, assuming we are using the International System of Units)

t is the time, hence its unit is s (seconds)

So, the expression is rewritten as:

m=as^{2}+bs+c

Since the left side of the equation is in meters, the right side must be in meters as well.

In addition, in the right side we have terms that have to added, this means each term must be in meters:

- For the first term a must be in units of \frac{m}{s^{2}} in order to have meters.

- For the second term b must be in units of \frac{m}{s} in order to have meters.

- For the third term c must be in units of m in order to have meters.

4 0
4 years ago
You are on the roof of the physics building, 46.0 above the ground . Your physics professor, who is 1.80 tall, is walking alongs
Fudgin [204]

Answer:

3.6m

Explanation:

if you are at a building that is 46m above the ground, and the professor is 1.80m, the egg must fall:

46m - 1.80m = 44.2m

the egg must fall for 44.2m to land on the head of the professor.

Now, how many time this takes?

we have to use the following free fall equation:

h=v_{0}t+\frac{1}{2}gt^2

where h is the height, v_{0} is the initial velocity, in this case v_{0}=0. g is the acceleration of gravity: g=9.81m/s and t is time, thus:

h=\frac{1}{2}gt^2

clearing for time:

2h=gt^2\\\frac{2h}{g}=t^2\\\sqrt{\frac{2h}{g}} =t

we know that the egg has to fall for 44.2m, so h=44.2, and g=9.81m/s, so we the time is:

t=\sqrt{\frac{2(44.2m)}{9.8m/s^2} }=\sqrt{\frac{88.4m}{9.81m/s^2} } =\sqrt{9.011s^2}= 3.002s

Finally, if the professor has a speed of v=1.2m/s, it has to be at a distance:

d=vt

and t=3.002s:

d=(1.2m/s)(3.002s)=3.6m

so the answer is the professor has to be 3.6m far from the building when you release the egg

7 0
3 years ago
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