Answer : The correct option is, (D)
Explanation : Given,
Concentration of
= 3 M
Concentration of
= 1 M
Concentration of
= 2 M
The given balanced equilibrium reaction is,
The expression for equilibrium constant for this reaction will be,
Now put all the given values in this expression, we get the value of
Therefore, the value of
for the given reaction is, 1.125
Neon, Helium, Krypton, Xenon, Argon
1) Chemical reaction: 2Al + 3Br₂ → 2AlBr₃.
m(Al) = 3,0 g.
m(Br₂) = 6,0 g.
n(Al) = m(Al) ÷ M(Al).
n(Al) = 3,0 g ÷ 27 g/mol.
n(Al) = 0,11 mol.
n(Br₂) = n(Br₂) ÷ m(Br₂).
n(Br₂) = 6 g ÷ 160 g/mol.
n(Br₂) = 0,0375 mol; limiting reagens.
n(Br₂) : n(AlBr₃) = 3 : 2.
n(AlBr₃) = 0,025 mol.
m(AlBr₃) = 0,025 mol · 266,7 g/mol.
m(AlBr₃) = 6,67 g.
2) m(Br₂) - all bromine reacts, so mass of bromine after reaction is zero grams (m(Br₂) = 0 g).
n(Al) = 0,11 mol - 0,025 mol = 0,085 mol.
m(Al) = 0,085 mol · 27 g/mol.
m(Al) = 2,295 g.
m(AlBr₃) = 6,67 g · 0,72 (yield of reaction).
m(AlBr₃) = 4,8 g.
n - amount of substance.
M - molar mass.
The answer is A because it cannot be B because that is ethylene and not D because it needs a subscript of 2 since it is a diatomic and it is no C because it is not carbon dioxide its oxygen