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Bond [772]
4 years ago
15

To find the mass defect for uranium-238 several calculations must be made. Which is the calculation that should be made first? A

ssume atomic number for uranium-238 is 92.
A.
92(1.0073) x 92(1.0087) =
B.
92(1.0073) x 146(1.0087) =
C.
146(1.0073) x 238(1.0087) =
D.
238(1.0073) x 238(1.0087) =
Physics
1 answer:
BaLLatris [955]4 years ago
3 0

mass number of uranium 238 is sum of number of proton and neutrons in it

While atomic number is just number of protons

So total number of protons in it = 92

total number of neutrons in it = 238  - 92 = 146

mass of proton = 1.0073 amu

mass of neutron = 1.0087 amu

now for the calculation of mass of nuclei is given as

M = zm_p + (A-z)m_n

M = 92(1.0073) + 146(1.0087)

so option B is correct

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Assume that the average mass of each of the approximately 1 billion people in China is 55 kg.Assume that they all gather in one
Harman [31]

Answer: 5.9(10)^{-8} m

Explanation:

The equation to calculate the center of mass C_{M} of a particle system is:

C_{M}=\frac{m_{1}r_{1}+m_{1}r_{1}+...+m_{n}r_{n}}{m_{1}+m_{2}+...+m_{n}}

In this case we can arrange for one dimension, assuming the geometric center of the Earth and the ladder are on a line, and assuming original center of mass located at the Earth's geometric center:

C_{M}=\frac{m_{E}(0 m) + m_{p} r_{E-p}}{m_{E}+m_{p}}

Where:

m_{E}=5.9(10)^{24} kg is the mass of the Earth

m_{p}=55(10)^{9} kg is the mass of 1 billion people

r_{E}=6371000 m is the radius of the Earth

r_{E-p}=6371000 m- 2m=6370998 m is the distance between the center of the Earth and the position of the people (2 m above the Earth's surface)

C_{M}=\frac{m_{p}55(10)^{9} kg (6370998 m)}{5.9(10)^{24} kg+55(10)^{9} kg}

C_{M}=5.9(10)^{-8} m This is the displacement of Earth's center of mass from the original center.

8 0
3 years ago
A flowerpot falls from a window sill 36.5 m
hram777 [196]

When a flowerpot falls from a window sill 36.5 m

above the sidewalk, then the velocity of the flowerpot is 26.7 m/s.

From Newton's third equation of motion,

v^2 = u^2 + 2gh

where,

h is the height of the object or body from ground

u is the initial velocity of the body or object

v is the final velocity of the body or object

g is the acceleration due to gravity

Now, as we know that

Flowerpot is at rest. So, u = 0

g = 9.81m/s^2

h = 36.5m

By substituting all the values, we get

v^2 = 2 × 9.81 × 36.5

= 716.13

v = 26.7m/s

Thus, we concluded that when a flowerpot falls from a window sill 36.5 m

above the sidewalk, then the velocity of the flowerpot is 26.7 m/s.

learn more about Newton's equation of law of motion:

brainly.com/question/8898885

#SPJ9

7 0
1 year ago
What is formula of perimeter of half circle​
OLga [1]

1/2 × 2 × pie × radius

= pie × radius

6 0
3 years ago
What kind of energy transformation takes place in a generator?
STALIN [3.7K]

Answer:

B. mechanical to electrical

3 0
3 years ago
Study the image of a circuit.
IRISSAK [1]
B is the correct answer . That make the most sense
5 0
4 years ago
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