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2 years ago

13

There are 13 boys are 4 girls in the jazz band find the ratio of the number of boys in the band to the total number of students

in the band

1 answer:

Nikitich [7]2 years ago

7 0

13:17 b/c 13 + 4 =17...

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A Force of 20N displaces a body about 45m how much work is done?

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Answer:

159 ofc

Explanation:

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Which type of stress leads to which type of strain that will lead to which type of surface expression , and cause a reverse faul

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2 years ago

A 0.20-kg block rests on a frictionless level surface and is attached to a horizontally aligned spring with a spring constant of

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Answer:

$0.57 ms^{-1}$

Explanation:

k = spring constant of the spring = 40 Nm⁻¹

A = amplitude of the simple harmonic motion = 4 cm = 0.04 m

m = mass of the block attached to spring = 0.20 kg

w = angular frequency of the simple harmonic motion

Angular frequency of the simple harmonic motion is given as $w = \sqrt{\frac{k}{m} } \\w = \sqrt{\frac{40}{0.20} }\\w = 14.14 rads^{-1}$

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Speed of the block as it pass the equilibrium point is given as

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2 years ago

As an admirer of Thomas Young, you perform a double-slit experiment in his honor. You set your slits 1.15 mm apart and position

Artist 52 [7]

Answer:

The distance of the first bright fringe is given as $Y_C = 1.22 *10^{-3}m$

The distance of the second dark fringe from the central bright fringe is given as $Y_D = 0.00192 \ m$

Explanation:

From the question we are told that

The slit separation distance is $d = 1.15 mm = \frac{1.15}{1000} =0.00115 m$

The distance of the slit from the screen is $D = 3.23 m$

The wavelength is $\lambda = 633 nm$

For constructive interference to occur the distance between the two slit is mathematically represented as

$Y_C =\frac{m \lambda D}{d}$

Where m is the order of the fringe which has a value of 1 for first bright fringe

Substituting values

$Y_C = \frac{1 * 633 *0^{-9} * 3.23}{0.00115}$

$Y_C = 1.22 *10^{-3}m$

For destructive interference to occur the distance between the two slit is mathematically represented as

$Y_D = [n + \frac{1}{2} ] \frac{\lambda D}{d}$

m = 2

so the formula to get the dark fringe is $n = \frac{1}{2} * 1$

$n=1$

Now substituting values

$Y_D = [ 1 + \frac{1}{2} ] * \frac{633 *10^{-9} * 3.23 }{0.00115}$

$Y_D =1.5 * \frac{633 *10^{-9} * 3.23 }{0.00115}$

$Y_D = 0.00192 \ m$

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2 years ago

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I use the impulse momentum formula.
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