what is the necessary condition on a force the result the conservation of angular momentum for a particle affected by that force
1 answer:
Answer:
The necessary condition is that the force that is applied should not be able to produce any torque about the axis of rotation which is achieved only if the force passes through the axis of rotation.
Explanation:
Mathematically the angular momentum is related to force as
where
'r' is arm of the force 'F'
For angular momentum to be conserved the right hand side of the above equation should be zero which can happen only if:
1) F = 0
2) r = 0
3) F and r are parallel.
Thus fulfilling any of the above condition shall conserve the angular momentum of a particle.
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The north celestial pole (and also the south) are described as two imaginary points that project on the axis of rotation of the earth, indefinitely towards space and that intersects with the celestial sphere (Remember that the earth has a slight inclination with respect to to its axis of rotation). The north and south celestial poles are directly above the head of someone located at the north or south pole of the earth.
Correct Answer is A.
Answer:
A solenoid field is increased with the increase in the current flow through the coil.
Explanation:
A solenoid is a current carrying coil with a significant number of loops. It works like an electromagnet inside which, a uniform and strong magnetic field is created. The magnetic field outside the solenoid field is nearly zero but not exactly zero.
While experimenting with the solenoid, scientists came to know that the magnetic field generated by the solenoid increases with the increase in the current, flowing through the solenoid.
The magnetic field works strongly around the arena of coil. The field changes its direction only near the ends and gets weak. Else its uniform throughout the loops.
The magnetic field inside the solenoid can be formulated as,
Where,
B = Magnetic field generated by the solenoid
= Constant
I = Current flowing through the loops of the solenoid
Answer:
speed of water is 0.0007138m/s
Explanation:
From the law of conservation of mass
Rate of mass accumulation inside vessel = mass flow in - mass flow out
so, dm/dt = mass flow in - mass flow out
taking p as density
where,
q(in) is the volume flow rate coming in
Q = is the volume of liquid inside tank at any time
But,
dQ = Adh
where ,
A = area of liquid surface at time t
h = height from bottom at time t
A = πr²
r is the radius of liquid surface
Hence,
so, the speed of water surface at height h
where,
is 75.7 L/min = 0.0757m³/min
h = 1.5m
so,
v = 0.04283 /60
v = 0.0007138m/s
Hence, speed of water is 0.0007138m/s