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mel-nik [20]
3 years ago
6

1. As a group, write down two challenges in terms of sustainability you would face when developing a sustainable food supply for

a Martian colony (or any area that is severely lacking in agricultural resources). Keep in mind the space and time limitations you have (1000 acres of growing space and several months’ worth of food).
2. A sustainable food supply requires more than just resource management. It also needs to provide people with suffi cient calories, macronutrients, and micronutrients for health, productivity, and well-being. Write down at least two challenges of producing such a diet sustainably in an area severely lacking in agricultural resources.
Physics
1 answer:
Stolb23 [73]3 years ago
7 0

Two sustainability challenges you would face when developing a sustainable food supply for a Martian colony would relate to Martian radiation and soil characteristics.

According to experiments carried out, Martian radiation is about 17 times more intense than on Earth, which impacts vegetation growth and crop quality.

Therefore, it is necessary to develop resources that enable a sustainable food supply in remote locations, such as for a Martian colony, as some production challenges may be related to food resistance and the amount of oxygen and water needed for growth.

Some solutions, therefore, could be planting in an underground shelter, which would be a controlled environment where conditions would be more favorable for the production of food with greater quality and diversity.

Learn more about sustainability here:

brainly.com/question/25713190

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what will happen to the fieldof view for each resultant magnification as you change objectives from 4 to 10 to 43
jonny [76]

Answer:

The field of view is reduced.

Explanation:

Given that,

The field of view for every resultant magnification like you change objectives from 4 to 10 to 43.

We know that,

Field of view :

When the view is observed at a point in a defined field then these field called field of view.

The normal angle of  field of view is 90°.

The formula of field of view is define as,  

field\ of\ view = \dfrac{field\ number}{magnification}

We can say that,

The field of view is inversely proportional to the magnification.

When magnification is low then field of view will be large.

When magnification is higher then field of view will be small .

According to question,  

When the magnification adjust from 4 to 10 to 43, the field of view is reduced.    

Hence, The field of view is reduced.

7 0
3 years ago
Please help I'm dispirit.
Natasha_Volkova [10]

Synthesis and decomposition reactions are  b. Synthesis and decomposition reactions are opposites of each other. Synthesis reactions are in the form A + B → AB, while decomposition reactions are in the form AB → A + B.

Synthesis reactions are reactions in which elements or compounds combine to form a larger compound. They are of the form A + B → AB.

Example: Na(s) + Cl (g)→ NaCl(s)

Decomposition reactions are reactions in which a larger compound breaks up into smaller compounds or elements. They are of the form AB → A + B.

Example: CaCO₃(s) → CaO (s) + CO₂ (g)

Synthesis and decomposition reactions are opposite of each other since synthesis reactions, new substances are formed while in decomposition reactions the compound is broken down into into smaller constituents.

So, Synthesis and decomposition reactions are  b. Synthesis and decomposition reactions are opposites of each other. Synthesis reactions are in the form A + B → AB, while decomposition reactions are in the form AB → A + B.

Learn more about reactions here:

brainly.com/question/282113

3 0
3 years ago
A Micro –Hydro turbine generator is accelerating uniformly from an angular velocity of 610 rpm to its operating angular velocity
Salsk061 [2.6K]

Answer:

Angular displacement of the turbine is 234.62 radian

Explanation:

initial angular speed of the turbine is

\omega_i = 2\pi f_1

\omega_1 = 2\pi(\frac{610}{60})

\omega_1 = 63.88 rad/s

similarly final angular speed is given as

\omega_f = 2\pi f_2

\omega_2 = 2\pi(\frac{837}{60})

\omega_2 = 87.65 rad/s

angular acceleration of the turbine is given as

\alpha = 5.9 rad/s^2

now we have to find the angular displacement is given as

\theta = \omega t + \frac{1}{2}\alpha t^2

\theta = (63.88)(3.2) + (\frac{1}{2})(5.9)(3.2^2)

\theta = 234.62 radian

3 0
3 years ago
QUICKK I NEED HELP!!<br> How is a mineral different from an element rock
Irina18 [472]

Answer:here you goo

Explanation:

A mineral is a naturally occurring inorganic element or compound having an orderly internal structure and characteristic chemical composition, crystal form, and physical properties. ... A rock is an aggregate of one or more minerals, or a body of undifferentiated mineral matter.

7 0
3 years ago
Read 2 more answers
(a) Find the frequency of revolution of an electron with an energy of 114 eV in a uniform magnetic field of magnitude 46.7 µT. (
stira [4]

Answer:

(a)  1.3 x 10^6 Hz

(b) 76.73 cm

Explanation:

(a)

the formula for the frequency is given by

f = B q / 2 π m

where, B be the strength of magnetic field, q be the charge on one electron, m is the mass of one electron.

B = 46.7 micro tesla = 46.7 x 10^-6 T

q = 1.6 x 10^-19 C

m = 9.1 x 10^-31 kg

f = (46.7 x 10^-6 x 1.6 x 10^-19) / (2 x 3.14 x 9.1 x 10^-31) = 1.3 x 10^6 Hz

(b) K = 114 eV = 114 x 1.6 x 10^-19 J = 182.4 x 10^-19 J

K = 1/2 mv^2

182.4 x 10^-19 = 0.5 x 9.1 x 10^-31 x v^2

v = 6.3 x 10^6 m/s

r = m v / B q

Where, r be the radius of circular path

r = (9.1 x 10^-31 x 6.3 x 10^6) / (46.7 x 10^-6 x 1.6 x 10^-19)

r = 0.7673 m = 76.73 cm  

5 0
4 years ago
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