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Ilia_Sergeevich [38]
2 years ago
14

Calculate the wavelength of a photon of light having a frequency of 3.50 x 1015 Hz.

Chemistry
1 answer:
Aliun [14]2 years ago
4 0

Answer:

Wavelength, \lambda=8.57\times 10^{-8}\ m

Explanation:

Given that,

Frequency, f=3.5\times 10^{15}\ Hz

We need to find the wavelength of a photon of light. The relation between frequency and wavelength is as follows :

c=f\lambda\\\\\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{3.5\times 10^{15}}\\\\\lambda=8.57\times 10^{-8}\ m

So, the wavelength of the light is 8.57\times 10^{-8}\ m.

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Calculate the volume in mL of 0.279 M Ca(OH)2 needed to neutralize 24.5 mL of 0.390 M H3PO4 in a titration.
Vsevolod [243]

The volume of the 0.279 M Ca(OH)₂ solution required to neutralize 24.5 mL of 0.390 M H₃PO₄ is 51.4 mL

<h3>Balanced equation </h3>

2H₃PO₄ + 3Ca(OH)₂ —> Ca₃(PO₄)₂ + 6H₂O

From the balanced equation above,

  • The mole ratio of the acid, H₃PO₄ (nA) = 2
  • The mole ratio of the base, Ca(OH)₂ (nB) = 3

<h3>How to determine the volume of Ca(OH)₂ </h3>
  • Molarity of acid, H₃PO₄ (Ma) = 0.390 M
  • Volume of acid, H₃PO₄ (Va) = 24.5 mL
  • Molarity of base, Ca(OH)₂ (Mb) = 0.279 M
  • Volume of base, Ca(OH)₂ (Vb) =?

MaVa / MbVb = nA / nB

(0.39 × 24.5) / (0.279 × Vb) = 2/3

9.555 / (0.279 × Vb) = 2/3

Cross multiply

2 × 0.279 × Vb = 9.555 × 3

0.558 × Vb = 28.665

Divide both side by 0.558

Vb = 28.665 / 0.558

Vb = 51.4 mL

Thus, the volume of the Ca(OH)₂ solution needed is 51.4 mL

Learn more about titration:

brainly.com/question/14356286

5 0
2 years ago
Why is oxygen written with a subscript 2 in CO2?
Alexeev081 [22]

Answer:

Explanation:

the answer is b

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At a given temperature, 4.06 atm of H2 and 3.5 atm of Cl2 are mixed and allowed to come to equilibrium. The equilibrium pressure
Llana [10]

<u>Answer:</u> The value of K_p for the given chemical reaction is 0.1415

<u>Explanation:</u>

Equilibrium constant in terms of partial pressure is defined as the ratio of partial pressures of the products and the reactants each raised to the power their stoichiometric ratios. It is expressed as K_p

For a general chemical reaction:

aA+bB\rightarrow cC+dD

The expression for K_p is written as:

K_p=\frac{p_{C}^cp_{D}^d}{p_{A}^ap_{B}^b}

For the given chemical equation:

H_2(g)+Cl_2(g)\rightleftharpoons 2HCl(g)

The expression for K_p for the following equation is:

K_p=\frac{(p_{HCl})^2}{(p_{H_2)}(p_{Cl_2})}

We are given:

p_{HCl}=1.418atm\\p_{H_2}=4.06atm\\p_{Cl_2}=3.5atm

Putting values in above equation, we get:

K_p=\frac{(1.418)^2}{(4.06)\times (3.5)}\\\\K_p=0.1415

The value of K_p for the given chemical reaction is 0.1415

5 0
3 years ago
Given the unbalanced equation: al + cuso4 --&gt; al2(so4)3 + cu. when properly balanced, the sum of the balancing coefficients i
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2Al + 3CuSO₄  =  Al₂(SO₄)₃ + 3Cu

∑=2+3+1+3=9

c. 9
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2 years ago
if the mass of the skate bored doubled but the net force on it remained constant, what would happen to the skate bored's acceler
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The skateboard's acceleration would decrease.

The larger the mass of an object, the more force is required to move it.
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